Take out a common factor between 3x and kx. That means use the distributive law to get what you normally would start with.
x(k + 3) = 4
Now divide by k + 3
x = 4/(k + 3)
That's as much as you can do with this question.
Total weight = 50 lb
x = number of 3-lb weights
y = number of 10-lb weights
weight of 3-lb weights = 3x
weight of 10-lb weights = 10y
total weight = 3x + 10y
equation
3x + 10y = 50
Answer:
Darius is correct if only the median score is considered.
Step-by-step explanation:
Darius scores are; 96, 54,120, 87, 123
arrange the scores in increasing order;
54,87,96,120,123
mean = (54+87+96+120+123)/5 =480/5 =96
median =96
Barb's scores are 92,94,96,98,110
mean=(92,94,96,98,110)/5 =490/5=98
median score=96
⇒if the median score only is considered; then it is a tie because the score is 96 in both players.
Answer: 
Step-by-step explanation:
<h3>
The complete exercise is: " A theatre has the capacity to seat people across two levels, the Circle, and the stalls. The ratio of the number of seats in the circle to a number of seats in the stalls is 2:5. Last Friday, the audience occupied all the 528 seats in the circle and
of the seats in the stalls. What is the percentage of occupancy of the theatre last Friday?"</h3>
Let be "s" the total number of seats in the Stalls.
The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is
.
Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:

Solving for "s", we get:

So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:
We know that
of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:

Therefore, the total number of seats that were occupied las Friday is:
Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:

Solving for "p", we get:

Answer: 0.46, 0.056, the distribution is approximately normal
Step-by-step explanation: The shape is approximately normal since the expected number of successes equals 36.8 and the expected number of failures equals 43.2 are both larger than 10