I got this T_T y=175-35t
But maybe its y= -35t + 175 since its negative :)
If we let x as candy A
y as candy B
a as dark chocolate in candy a
b as dark chocolate in candy b
c as caramel
d as walnut
P as profit
we have the equations:
a + c = x
2b + d = y
a + 2b ≤ 360
c ≤ 430
d ≤ 210
P = 285x + 260y
This is an optimization problem which involves linear programming. It can be solved by graphical method or by algebraic solution.
P = 285(a + c) + 260(2b +d)
If we assume a = b
Then a = 120, 2b = 240
P = 285(120 + 120) + 260(240 + 120)
P = 162000
candy A should be = 240
candy B should be = 360
Answer:
A. 6 units left and 9 units down
Step-by-step explanation:
Given:
y = (x – 5)^2 + 7
y = (x +1)^2 - 2
The graph of y = (x – 5)^2 + 7 is a parabola 5 units right and 7 units up
The graph of y = (x +1)^2 - 2 is a parabola 1 unit left and 2 units down
Transformation is the difference in the shift
Transformation = 6 units left and 9 units down.
Therefore, answer A. 6 units left and 9 units down
Hope this will helpful.
Thank you.
Serious high school. This is one of the few differential equations I can solve.
The usual particular solution is
because
is its own derivative.
An independent solution is
which has a negative sign in the first derivative which turns back to positive in the second.
The arbitrary linear combination spans the solution space:

But we only are asked for the basis.
Answer:
Answer:
Kindly check explanation
Step-by-step explanation:
Experiment of tossing a coin twice :
A.) Experimental outcome:
Head = H ; Tail = T ;
Head and Head = HH
Tail and Tail = TT
Head and Tail = HT
Tail and Head = TH
Number of head(s) on toss = z
C)
Experimental outcome ___number of heads(z)
HH _____________________2
TT _____________________ 0
TH _____________________ 1
HT _____________________ 1
D) the random variables defined are discrete because they are only take up integer values within a specified range