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Lilit [14]
2 years ago
6

A ship travels due west for 60 miles. It then travels in a northwest direction for 85 miles and ends up 119 miles from its origi

nal position. To the nearest tenth of a degree, how many degrees north of west did it turn when it changed direction? Show your work.
Mathematics
1 answer:
Bumek [7]2 years ago
5 0
Given:
due west: 60 miles
northwest: 85 miles
original point to destination point: 119 miles

Let us use the Law of Cosines to find the angle.

119² = 60² + 85² - [(2*60*85)*cos(x)]
14,161 = 3600 + 7225 - (10,200 * cos(x))
14,161 = 10,825 - 10,200 cos(x)
14,161 - 10,825 = -10,200 cos(x)
3.336 = -10,200 cos(x)
3,336 / -10,200 = cos(x)
-0.3271 = cos(x)
-0.3271 / cos = x
cos^-1 (-0.3271) = x
109.09 = x

109.09° or 109.10° north of west.
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Ratio for 669 and 221
alexandr402 [8]

Hello from MrBillDoesMath!

Answer:

669/221

Discussion:

Ratio of 669 to 221 =  669/221.

Now,  669 = 3 * 223 and 221  = 13 * 17. Note that all numbers involved in the factorizations are distinct primes so nothing cancels out in their ratio. That is,

669/221 can not be reduced further.


Thank you,

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5 0
2 years ago
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Find the amount of time.<br> I=$450, P=$2400, r=7.5%<br> Help!
faust18 [17]
I = PRT.....rearrange = I / PR = T
I = 450
R = 7.5%...turn to decimal = 0.075
P = 2400

I / (PR) = T
450 / (2400 * 0.075) = T
450 / 180 = T
2.5 = T...so time is 2.5 years, or 2 1/2 years
8 0
2 years ago
2.5 kg of cabbages cost £1.20<br><br> Work out the cost of 3.75 kg
s2008m [1.1K]
Thank you for your question!

In order to get the cost of 1 kg of cabbage, divide the cost by the quantity:

1.20/2.5
0.48

Now, multiply the amount for 1 kg to 3.75, because you need 3.75 times the amount.

0.48 * 3.75
1.80

So, it would cost 1.80 pounds for 3.75 kg.
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8 0
2 years ago
The general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0. The equation of this circle in standard form is
Ede4ka [16]

Answer:

The standard form of a circle is (x-h)^2 + (y-k)^2 = r^2 with (h,k) being the center of the circle and r being the radius. In this case the circle's equation in standard form is (x-2)^2 + (y+3)^2 = 18. Knowing this it's easy to see that the center of the circle (h,k) is (2,-3). Finally the radius is \sqrt{18} or in simplified terms, 3\sqrt{2}

Step-by-step explanation:

7 0
2 years ago
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Prove tan3A= (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) ...?
aivan3 [116]
The solution to the problem is as follows:

<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
 
and
 
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Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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