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kirill115 [55]
2 years ago
15

The student’s council is setting up a concession stand for a 24 hour relay. They plan on selling hot dogs hamburgers. A maximum

of 600 hamburgers and hot dogs are needed. From the previous year’s relay the demand should be at least four times as many hot dogs as hamburgers
a) define the variables.
b) write a system of linear inequalities to represent this situation
Mathematics
2 answers:
kozerog [31]2 years ago
4 0
For this item, we let the number of hotdogs to be sold be x and that the number of hamburgers will be y. The system of linear inequality that would represent this scenario is,
                                   x + y ≤ 600
                                   x ≥ 4y
Alchen [17]2 years ago
3 0

Answer with explanation:

Maximum Number of hamburgers and Hot Dogs required for the Relay =600

Let number of Hamburgers =a

And Number of Hot dogs = b

So, In terms of Inequality, the above statement can be written as:

1.⇒  a+b ≤ 600

It is also given that, Demand of Hot Dogs should be at least four times as Hamburgers.

 So,this statement in terms of Inequality can be written as:

      ⇒ Demand of Hot Dogs ≥ 4 × Demand of Hamburgers

     2 ⇒ b ≥ 4 a

⇒Here,a and b are Variables Representing, number of Hamburgers ,and Number of Hot dogs Respectively.

And, the system of Linear inequalities representing this situation is

     a+b ≤ 600

      b ≥ 4 a

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11) The Cost of maintaing a
dezoksy [38]

Answer:

a). Cost of 44 pupils = $14265

b). Least number of pupils = 31

Step-by-step explanation:

The given question is incomplete; here is the complete question.

The cost of maintaining a school is partly constant and partly varies as the number of pupils. With 50 pupils, the cost is $15,705.00 and with 40 pupils, it is $13,305.00.

(a) Find the cost when there are 44 pupils.

(b) If the fee per pupil is $360.00, what is the least number of pupils for which the school can run without a loss?

Let the equation representing the total cost of maintaining a school is,

C = ax + b

Where C = Total cost of maintaining a school

a = Fee per pupil

b = Fixed running cost

x = number of pupils

a). Cost of 50 pupils = $15705

    Equation will be,

    15705 = 50a + b -------(1)

    Cost of 40 pupils = $13305

    Equation will be,

    13305 = 40a + b --------(2)

    By subtracting equation (2) from equation (1),

    15705 - 13305 = (50a + b) - (40a + b)

    2400 = 10a

    a = 240

    From equation (1),

    b = 3705

    Equation representing the total cost will be,

    C = 240x + 3705

    If x = 44

    C = 240(44) + 3705

    C = $14265

b). If the fee per pupil 'a' = $360

    Let the number of pupils = p

    Total fee of 'p' pupils = $360p

    Total cost to run the school will be = 3705 + 240p

    For the school not to be in the loss,

    360p ≥ 3705 + 240p

    360p - 240p ≥ 3705

    120p ≥ 3705

    p ≥ \frac{3705}{120}

    p ≥ 30.875

    Therefore, to run the school without loss, number pupils should be at least 31.

3 0
2 years ago
A direct variation function contains the points (–9, –3) and (–12, –4). Which equation represents the function?
Natasha_Volkova [10]
First, find the slope between the two points. 
Slope = y2-y1 / x2-x1
-4+3/ -12+9
-1/-3
1/3 is the slope of this equation. 
You do not have to go any further to find b or the y-intercept because it appears that b or the y-intercept is 0 in this case. 
y= 1/3x or in other words y= x/3
4 0
2 years ago
Read 2 more answers
The ballpark made a total of $15,000 from ticket sales at Wednesday's game. The ballpark charges $20 for each adult ticket and $
IRISSAK [1]
<h3>Answer:</h3>

equations

  • 20a +10c = 15000
  • c = 3a

solution

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<h3>Step-by-step explanation:</h3>

Let "a" and "c" represent the numbers of adult and children's tickets sold, respectively. The problem statement tells us two relationships between these values:

... 20a +10c = 15000 . . . . . . total revenue from ticket sales

... c = 3a . . . . . . . . . . . . . . . . relationship between numbers of tickets sold

Using the expression for c, we can substitute into the first equation to get ...

... 20a +10(3a) = 15000

... 50a = 15000

... a = 15000/50 = 300 . . . . . adult tickets sold

... c = 3·300 = 900 . . . . . children's tickets sold

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mash [69]

Answer:

$23.40

Step-by-step explanation:

You have to subtract $39.75 by $16.35 as $39.75 is the total and we have to find out how much the bracelet is. There is also no regrouping.

7 0
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grandymaker [24]
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