9514 1404 393
Answer:
40·713 and 8·713
Step-by-step explanation:
When this multiplication is carried out "by hand", the usual sum of partial products is ...
8·713 + 40·713
Answer:
1) 120
2) E (Z) = 12 and Variance of Z = 90
a) 5 liters
Step-by-step explanation:
1. We can find this by suing combinations.
Here n= 10 and r= 3 so n C r
= 10 C 3= 120
2. E(X) = 8 and E(Y) = 3
Z = 2X - 3Y +5
E(Z ) = 2 E (X) - 3(E)(Y) +5 ( applying property for mean)
= 2(8) - 3(3)+ 5 = 16+5-9= 21-9= 12
V(X) = 9 and V(Y) = 6.
V(Z) = E(Z )²- V(X) *V(Y) (applying property for Variance for two variables )
= 144- 54= 90
3. 55 liters contain adulterated milk in 7: 4.
So it contains 4/ 11*55= 20 liters of water
But we want to make it a ratio of 7:6
the water will be 6/13 *55= 25.38 when rounded gives 25 liters of water
So 25- 20 = 5 liters must be added to make it a ratio of 7:6
Step-by-step explanation:
1024 bytes = 1 kb
n kb = 1024 × n b
Where n is a positive number
Answer:
x = 
Step-by-step explanation:
Since it will be easier, just set "ce" as one term. Let ce = y
You are solving for the variable, x. Note the equal sign, what you do to one side, you do to the other.
Do the opposite of PEMDAS.
First, subtract 4 from both sides:
y = 7x + 4
y (-4) = 7x + 4 (-4)
y - 4 = 7x
Next, Divide 7 from both sides:
(y - 4)/7 = (7x)/7
(y - 4)/7 = x
x = (y/7) - (4/7)
Your value of x is
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