Question

The steps in writing f(x) = 18x + 3x2 in vertex form are shown, but a value is missing in the last step. Write the function in standard form. f(x) = 3x2 + 18x Factor a out of the first two terms. f(x) = 3(x2 + 6x) Form a perfect square trinomial. f(x) = 3(x2 + 6x + 9) – 3(9) Write the trinomial as a binomial squared. f(x) = 3(x + ______)2 – 27

Answer 1

To find the vertex form of parabola $y=a(x-x_0)^2+y_0$ given in almost standard form $y=ax^2+bx+c,$ were written following steps:

1.  Write the function in standard form:

$y=3x^2+18x.$

2. Factor a out of the first two terms:

$y=3(x^2+6x).$

3. Form a perfect square trinomial:

$y=3(x^2+6x+9-9)=3(x^2+6x+9)-3\cdot 9.$

4. Write the trinomial as a binomial squared:

$y=3(x+3)^2-27.$

The vertex is (-3,-27).

Answer: missing value is 3

Answer 2

Answer:

A on e2020

Step-by-step explanation: