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bonufazy [111]
2 years ago
13

True or False? The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is th

e circles radius

Mathematics
2 answers:
Ratling [72]2 years ago
6 0
Itis true <span>The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is the circles radius</span>
ivolga24 [154]2 years ago
3 0

Answer:

True, This is circumcentre point of triangle.

Step-by-step explanation:

The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is the circles radius.

This is a circumcenter point of triangle whose distance from each vertex is same.

Circumcenter of triangle is a point of intersection of perpendicular bisector of the sides of triangle.

Please see the attachment.

If we draw a circle from a point circumcenter it will touches all three vertices of triangle.

The distance from centre of circle to point on circle is known as radius.

Thus, Statement is true.

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Find the missing term. () + (7 − 3i) + (5 + 9i) + 13i = 10 − 5i.
kotegsom [21]
X + (7 - 3i) + (5 + 9i) + 13i = 10 - 5i

Subtract 13i from both sides

x + (7 -3i) + (5 + 9i) = 10 - 18i

Subtract (5 + 9i). MAKE SURE YOU SUBTRACT 9i TOO. In other words, distribute the negative and subtract 5 and 9i at the same time.

x + (7 - 3i) = 5 - 27i

Do the same with (7 - 3i). You'll be adding 3i since -(-3i) = 3i.

x = -2 - 24i
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Answer:

Your correct answer is d. Harry and Helen will receive a refund of $555. explain please

Step-by-step explanation:

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2 years ago
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Marisa drank one cup of milk and ate x small vanilla cookies for a snack. The linear equation below represents y, the total numb
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Try doing the research for yourself. you might actually learn something new in the process.
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2 years ago
given the points A(-3,-5) and B (5,0), find the coordinates of the point P on a directed line segment AB that partitions AB in t
Sonja [21]

\bf ~~~~~~~~~~~~\textit{internal division of a line segment} \\\\\\ A(-3,-5)\qquad B(5,0)\qquad \qquad \stackrel{\textit{ratio from A to B}}{2:3} \\\\\\ \cfrac{A\underline{P}}{\underline{P} B} = \cfrac{2}{3}\implies \cfrac{A}{B} = \cfrac{2}{3}\implies 3A=2B\implies 3(-3,-5)=2(5,0)\\\\[-0.35em] \rule{31em}{0.25pt}\\\\ P=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] \rule{31em}{0.25pt}


\bf P=\left(\cfrac{(3\cdot -3)+(2\cdot 5)}{2+3}\quad ,\quad \cfrac{(3\cdot -5)+(2\cdot 0)}{2+3}\right) \\\\\\ P=\left( \cfrac{-9+10}{5}~~,~~\cfrac{-15+0}{5} \right)\implies P=\left(\frac{1}{5}~,~-3  \right)

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2 years ago
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Given the function f(x) = −3x3 + 9x2 − 2x + 3, what part of the function indicates that the left end starts at the top of the gr
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Answer: The correct option is, The coefficient of the first term.

Step-by-step explanation:

The given function is,

f(x)=-3x^3+9x^2-2x+3

End behavior of the polynomial function : It is defined as the graph of f(x) as x approaches +\infty and -\infty.

The end behavior of the graph depends on the leading coefficient and degree of the polynomial.

As, the degree of the polynomial is '3'. So, the leading coefficient will determine the structure of the graph.

Therefore, the coefficient of the first term will indicate that the left end starts at the top of the graph.

The graph is also shown below.

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