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bonufazy [111]
2 years ago
13

True or False? The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is th

e circles radius

Mathematics
2 answers:
Ratling [72]2 years ago
6 0
Itis true <span>The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is the circles radius</span>
ivolga24 [154]2 years ago
3 0

Answer:

True, This is circumcentre point of triangle.

Step-by-step explanation:

The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is the circles radius.

This is a circumcenter point of triangle whose distance from each vertex is same.

Circumcenter of triangle is a point of intersection of perpendicular bisector of the sides of triangle.

Please see the attachment.

If we draw a circle from a point circumcenter it will touches all three vertices of triangle.

The distance from centre of circle to point on circle is known as radius.

Thus, Statement is true.

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A real estate agent sells two sites for Rs. 18000 each. On one he gains 25% and on the other he loses 25 %. What is his loss or
lidiya [134]

HOPE THIS WILL HELP YOU

3 0
2 years ago
Tim Tradesman estimates his taxable income will be $7,500. He is paid every two weeks or 26 times a year.
alisha [4.7K]
Given:
Taxable income: 7,500
Paid every two weeks or 26 weeks in a year

Based on 2007 Federal Income Tax Table for Single Taxpayer, Tim is under the tax range over $0 but not over $7,825. The tax is 10% of the amount over $0.

<span>1. Finds the tax rate for his income level =10 %

2. Enters the base amount = $7,500

3. Enters the amount of tax owed = $7,500 * 10% = $750

4. Divides by 26 = $750 / 26 = $28.85 tax withheld from biweekly wages.</span>
8 0
2 years ago
Read 2 more answers
Factorise 125x^3 -27y^3
telo118 [61]

Answer:

(5x - 3y)(25x² +15xy + 9y²)

Step-by-step explanation:

125x³ - 27y³ is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²)

Given

125x³ - 27y³

= (5x)³ - (3y)³

= (5x - 3y)((5x)² + (5x)(3y) + (3y)²)

= (5x - 3y)(25x² + 15xy + 9y²)

6 0
2 years ago
A particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls invol
bagirrra123 [75]

Answer:

a) 0.214 = 21.4% probability that at most 4 of the calls involve a fax message

b) 0.118 = 11.8% probability that exactly 4 of the calls involve a fax message

c) 0.904 = 90.4% probability that at least 4 of the calls involve a fax message

d) 0.786 = 78.6% probability that more than 4 of the calls involve a fax message

Step-by-step explanation:

For each call, there are only two possible outcomes. Either it involves a fax message, or it does not. The probability of a call involving a fax message is independent of other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

25% of the incoming calls involve fax messages

This means that p = 0.25

25 incoming calls.

This means that n = 25

a. What is the probability that at most 4 of the calls involve a fax message?

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.25)^{0}.(0.75)^{25} = 0.001

P(X = 1) = C_{25,1}.(0.25)^{1}.(0.75)^{24} = 0.006

P(X = 2) = C_{25,2}.(0.25)^{2}.(0.75)^{23} = 0.025

P(X = 3) = C_{25,3}.(0.25)^{3}.(0.75)^{22} = 0.064

P(X = 4) = C_{25,4}.(0.25)^{4}.(0.75)^{21} = 0.118

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.001 + 0.006 + 0.025 + 0.064 + 0.118 = 0.214

0.214 = 21.4% probability that at most 4 of the calls involve a fax message

b. What is the probability that exactly 4 of the calls involve a fax message?

P(X = 4) = C_{25,4}.(0.25)^{4}.(0.75)^{21} = 0.118

0.118 = 11.8% probability that exactly 4 of the calls involve a fax message.

c. What is the probability that at least 4 of the calls involve a fax message?

Either less than 4 calls involve fax messages, or at least 4 do. The sum of the probabilities of these events is 1. So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4). Then

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.25)^{0}.(0.75)^{25} = 0.001

P(X = 1) = C_{25,1}.(0.25)^{1}.(0.75)^{24} = 0.006

P(X = 2) = C_{25,2}.(0.25)^{2}.(0.75)^{23} = 0.025

P(X = 3) = C_{25,3}.(0.25)^{3}.(0.75)^{22} = 0.064

P(X

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.096 = 0.904

0.904 = 90.4% probability that at least 4 of the calls involve a fax message.

d. What is the probability that more than 4 of the calls involve a fax message?

Very similar to c.

P(X \leq 4) + P(X > 4) = 1

From a), P(X \leq 4) = 0.214)

Then

P(X > 4) = 1 - 0.214 = 0.786

0.786 = 78.6% probability that more than 4 of the calls involve a fax message

8 0
2 years ago
Find the first partial derivative:<br><br> f(x, y) = y^5 -3xy
Romashka-Z-Leto [24]
Partial derivative is derivative over only 1 variable.
here we have 2 variables so it depends on which variable you want to make partial derivative.

case 1. 
df/dx = -3y

case 2
df/dy = 5y^4 - 3x
8 0
2 years ago
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