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2 years ago

Please Help

Mathematics

2 answers:

charle [14.2K]2 years ago

8 0

It's c. I literally just answered it

ra1l [238]2 years ago

4 0

Answer:

Option: C is the correct answer.

$\dfrac{h}{4}=\dfrac{12}{5}$

Step-by-step explanation:

Clearly from the diagram shown we could see that the angle formed at the base is the same.

Let the angle be theta (θ).

Hence, in the small right angled triangle ΔACB we have:

$\tan \theta=\dfrac{AC}{CB}\\\\\tan \theta=\dfrac{4}{5}------(1)$

Similarly in the right angled triangle ΔEDB we have:

$\tan \theta=\dfrac{ED}{DB}\\\\\tan \theta=\dfrac{h}{12}------(2)$

Hence, on equating equation (1) and equation (2) we have:

$\dfrac{4}{5}=\dfrac{h}{12}\\\\\dfrac{h}{4}=\dfrac{12}{5}$

Hence, option:C is the correct option.

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Tom supports North Storm Football Club. At the match between North Storm and West Stanford there were 71,167 spectators. If 41,1

dangina [55]

Answer:
30,058 spectator

Explanation:
The total number of spectators is equal to the sum of West Stanford's and North Storm's supporters.
We are given that:
Total number of spectators = 71,167 spectator
North Storm spectators = 41,109 spectator
So, to get the number of West Stanford spectators, all we have to do is subtract North Storm spectators from the total spectators as follows:
West Stanford spectators = 71,167 - 41,109 = 30,058 spectator

Hope this helps :)

8 0

2 years ago

Jonah is thinking of a 2-digit number. It is a multiple of 6 and 12. It is a factor of 108. The sum of its digits is 9. What num

Colt1911 [192]

Answer:

Step-by-step explanation:

36x3=108

3+6=9

6 0

2 years ago

Read 2 more answers

What is the measure of Angle J K L? Triangle J K L . The exterior angle to angle K has a measure of 83 degrees. 83 degrees 97 de

nasty-shy [4]

Answer:

The measure of angle JKL is 97 degrees.

Step-by-step explanation:

Given:

A triangle JKL .

Measure of exterior angle K = 83 degrees

We have to find the measure of $\angle JKL$ .

In $(\triangle\ JKL)$ we see that the exterior angle is in linear pair with $\angle JKL$ .

Note:

Linear pair angles sum is 180 degree.

Let $\angle JKL$ be 'x' degrees .

So,

⇒ $x+83=180$

⇒ Subtracting 83 from both sides.

⇒ $x+83-83=180-83$

⇒ $x=180-83$

⇒ $x=97$ degrees

The measure of angle JKL in the triangle is of 97 degrees.

5 0

2 years ago

Read 2 more answers

PLEASE HELP!!!!!!

jek_recluse [69]

$\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}\\\\
-----------------------------\\\\

\begin{cases}
a=12\\
b=10\\
D=90+50
\end{cases}\implies d = \sqrt{{{ 12}}^2+{{ 10}}^2-2(12)(10)cos(140^o)}
\\\\\\
d\approx \sqrt{427.851}\implies d\approx 20.684551$