Answer:
B) The rates of ATP production and carbon dioxide production would both increase.
Explanation:
The citric acid cycle is the second stage of aerobic cellular respiration. It includes complete oxidation of acetyl CoA into CO2 and H2O. During the citric acid cycle, NAD and FAD serve as electron acceptors. Reduction of these reducing powers forms NADH and FADH2 which in turn enter the electron transport chain for their oxidation and drive the process of as many as 32 ATP molecules by oxidative phosphorylation. On the other hand, fermentation forms of 2 ATP molecules and a few or no CO2 molecules.
Therefore, if one of the eight intermediates of the citric acid cycle is added to the medium, the yeast cells would perform aerobic cellular respiration and would form more CO2 and ATP molecules than the ones formed during the process of fermentation.
Answer: Option (d) is the correct answer.
Explanation:
Nucleus of an atom consists of protons and neutrons. Protons are positively charged and neutrons have no charge. So, due to the like charges of protons there occurs electrostatic force of repulsion inside the nucleus of the atom.
But due to similar number of neutrons and protons a force that is able to bind both of them together is known as strong nuclear binding energy.
This force is strong enough that it is able to overcome electrostatic force of repulsion. But when there is great difference in the number of protons and neutrons then binding force is not strong enough.
Hence, the atom becomes unstable and undergoes radioactive decay. So, this means weak forces are responsible for radioactive decay.
Thus, we can conclude that the statement which best describes Yanni’s error is that the strong force is responsible for radioactive decay.
Answer:
Use a product that makes the dogs grow long hair a non harmful fertiliser could work
Explanation:
Answer:
A. Calcium would be transported to the sarcoplasmic reticulum therefore contractions would cease.
Explanation:
A muscle fibre will stop contraction immediately ATP is used up. Also, muscle contraction will end as soon as the information from the motor neuron stops. This repolarizes the sarcolemma and T-tubules, thereby closing the voltage-gated calcium channels in the sarcoplasmic reticulum. Calcium ions are then pumped back into the sarcoplasmic reticulum, in order for tropomyosin to cover the binding sites on the actin strands again.
Answer:
p = 0.34
Explanation:
The green allele is recessive, meaning two copies of q (qq) are required to be green. Conversely, animals that are either pp or pq will be blue.
If 44 organisms are green, that means 44 are qq.
For genotype frequencies, the equation is:
homozygous dominant genotype + heterozygous + homozygous recessive = 100%
Which is denoted as
p² + 2pq + q² = 1
We know that q² = 44/100 = 0.44
To work out q, we can do 
= 0.66
For allele frequencies, the total must add up to 100%, so
p + q =1
We know that q= 0.66
So p = 0.34, because 0.66 + 0.34 = 1
