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Drupady [299]
2 years ago
15

While designing a website, a(n) ____ allows you to identify the specific amount of space used on a particular page before it con

tains final content.
A: wireframe
B: index
C: draft
D: URL
Computers and Technology
2 answers:
Aleks [24]2 years ago
8 0
The answer would be A: wireframe, im pretty sure...

Hope this helped!! :)

Irina-Kira [14]2 years ago
6 0
I believe the answer is wireframe because wireframes allow a user to focus on the amount of content on a website, so i believe it's wireframe. 
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Float_abs - return bit-level equivalent of absolute value of f for * floating point argument f. * both the argument and result a
olga_2 [115]

#include <stdio.h>

int main(void) {

            // your code goes here

            //unsigned a =float_times_four(0x80000000);

            unsigned float_times_four(unsigned uf){

                unsigned expn = (uf >> 23) & 0xFF;

                printf(expn);

                unsigned sign = uf & 0x80000000;

                unsigned frac = uf & 0x007FFFFF;

                if(expn == 255 ||(expn == 0 && frac ==0))

                    return uf;

                if(expn){

                    expn<<2;

                }else if(frac == 0x007FFFFF){

//here 0x7FFFFF given by you that is wrong you place this 0x007FFFFF will excute

                    frac>>2;

                    expn<<2;

                }else{

                    frac<<=2;

                }

return (sign) | (expn <<23) | (frac);

            }

            return 0;

}

3 0
2 years ago
Define a class named ComparableSquare that extends Square (defined above) and implements Comparable. Implement the compareTo met
Alexxx [7]

Answer:

/*********************************************************************************

* (The ComparableCircle class) Define a class named ComparableCircle that        *

* extends Circle and implements Comparable. Draw the UML diagram and implement   *

* the compareTo method to compare the circles on the basis of area. Write a test *

* class to find the larger of two instances of ComparableCircle objects.         *

*********************************************************************************/

public class Exercise_13_06 {

/** Main method */

public static void main(String[] args) {

 // Create two instances of ComparableCircle objects

 ComparableCircle comparableCircle1 = new ComparableCircle(12.5);

 ComparableCircle comparableCircle2 = new ComparableCircle(18.3);

 // Display comparableCircles

 System.out.println("\nComparableCircle1:");

 System.out.println(comparableCircle1);

 System.out.println("\nComparableCircle2:");

 System.out.println(comparableCircle2);

 // Find and display the larger of the two ComparableCircle objects

 System.out.println((comparableCircle1.compareTo(comparableCircle2) == 1  

  ? "\nComparableCircle1 " : "\nComparableCircle2 ") +  

  "is the larger of the two Circles");

}

}

3 0
2 years ago
The success of Eye of the Storm exemplifies:
lyudmila [28]
A should be correct i think
6 0
2 years ago
Read 2 more answers
Respond to the following in a paragraph of no less than 125 words. Describe the steps to active listening.
Agata [3.3K]

Answer

• Maintaining eye contact

• Paying attention in the talk

• Listening without jumping to conclusion

• Formulating a picture in mind as you listen

• Avoid interruption to suggest solutions

• Asking clarification when the speaker has paused

• Asking questions to improve understanding

• Understanding the mood of the speaker

• Giving the appropriate feedback

Explanation

A person can improve his active listening skills by being aware of his or her personal style of communicating. A good listener is productive  and able to influence others when talking because he or she will have mastered the technique of persuading and negotiating with audience when talking. The journey to becoming an active listener is through paying attention, showing that you are following the speaker ,providing good feedback, avoiding judging the speaker and providing the appropriate feedback.



8 0
2 years ago
Read 2 more answers
Write a method printShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, prin
iogann1982 [59]

Answer:

import java.util.Scanner;

public class nu3 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter number of cycles");

       int numCycles = in.nextInt();

       //Call the method

       printShampooInstructions(numCycles);

   }

   public static void printShampooInstructions(int numCycles){

                if (numCycles<1){

              System.out.println("Too few");

          }

          if (numCycles>4){

              System.out.println("Too Many");

          }

          else {

              for (int i = 1;i <= numCycles; i++) {

                  System.out.println( numCycles+ ": Lather and rinse");

                  numCycles--;

              }

              System.out.println("     Done");

          }

   }

}

Explanation:

This is solved using Java programming language

The method printShampooInstructions() is in bold in the answer section

I have also provided a complete program that request user to enter value for number of cycles, calls the method and passes that value to it

The logic here is using if .... else statements to handle the different possible values of Number of cycles.

In the Else Section a loop is used to decrementally print the number of cycles

4 0
2 years ago
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