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2 years ago

How can you decompose the composite figure to determine its area?

Mathematics

2 answers:

laiz [17]2 years ago

6 0

see the attached figure to better understand the problem

we know that

The Area of the composite figure is equal to the sum of Area 1, Area 2 and Area 3

The Area 1 is a triangle

The Area 2 is a rectangle

The Area 3 is equal a semicircle

therefore

the answer is the option

a triangle, a rectangle, and a semicircle

Kipish [7]2 years ago

6 0

The option 4 $\boxed{{\mathbf{a triangle, a rectangle, and a semicircle}}}$ is correct.

Further explanation:

The given figure is the composite figure that involves some two dimensional shapes.

It can be better understand through the attached figure.

Option 1: Three triangles and a circle

It can be seen that in the given figure there is not any three triangles.

Therefore, option 1 is not correct.

Option 2: Two triangles, a rectangle and a circle.

It can be seen that in the given figure there is not any two triangles and a circle.

Therefore, option 2 is not correct.

Option 3: a triangle, a pentagon and a semicircle

It can be seen that in the given figure there is not any pentagon.

Therefore, option 3 is not correct.

Option 4: a triangle, a rectangle and a semicircle

It can be seen from the attached figure that there is one rectangle, one triangle, one semicircle.

The area of the combined figure is the sum of area 1, area 2, area 3 and area 4.

Area 1 represents the triangle, area 2 represents the rectangle, area 3 represents semicircle.

Therefore, option 4 is correct.

Learn more:

Learn more about the function is graphed below brainly.com/question/9590016

Learn more about the symmetry for a function brainly.com/question/1286775

Learn more about midpoint of the segment brainly.com/question/3269852

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Two dimensional figure

Keywords: triangle, rectangle, area, semicircle, pentagon, circle, figure, composite figure, combined figure, sum, decomposition, shapes

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A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time).

likoan [24]

Answer:

(a). 72.9%.

(b). 13.6 hr.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;

=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "

=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"

So, we will be making use of the Crawford learning curve model.

T(7) + 10 = T (17) = 30 min.

T(7) = T1(7)^b = 45.

T(17 ) = T1(17)^b = 30.

(T1) = 45/7^b = 30/17^b.

45/30 = 7^b/17^b = (7/17)^b.

1.5 = (0.41177)^b.

ln 1.5 = b ln 0.41177.

0.40547 = -0.8873 b.

b = - 0.45696.

=> 2^ -0.45696 = 0.7285.

= 72.9%.

(b). T1= 45/7^ - 045696 = 109.5 hr.

V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .

V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .

= 815.7 min .

= 13.595 hr.

8 0

2 years ago

The length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58° to 3

viva [34]

Answer:

119.45 m

Step-by-step explanation:

Given:

When angle of elevation of the sun changes from 58° to 36° the length of shadow of a pole increases by 90 m.

To find:

Length of pole = ?

Solution:

Kindly refer to the attached image.

$\triangle ABC$ represents the 1st angle of elevation of sun i.e. 58°

$\triangle ABD$ represents the 2nd angle of elevation of sun i.e. 36°

Change in shadow is represented by CD = 90 m

Let height of pole, AB = $h$ m

Let side BC = $x$ m

Now, let us apply tangent rules in $\triangle ABC, \triangle ABD$ one by one:

$tan\theta = \dfrac{Perpendicular}{Base}\\\Rightarrow tan58^\circ=\dfrac{AB}{BC}\\\Rightarrow tan58^\circ=\dfrac{h}{x}\\\Rightarrow x = 0.624h ..... (1)$

$tan36^\circ = \dfrac{h}{x+90}$

Putting value of $x$ using equation (1):

$tan36^\circ = \dfrac{h}{0.624h+90}\\\Rightarrow 0.726\times 0.624h+0.726\times 90 = h\\\Rightarrow h-0.453h =65.34\\\Rightarrow \bold{h = 119.45\ m}$