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ella [17]
2 years ago
6

David can proofread 15 reports in an hour, while Armando can proofread 37 reports in an hour. If they have 400 reports to proofr

ead, how much time will it take between the two of them?
Mathematics
1 answer:
Goshia [24]2 years ago
6 0

In order to know how much time will David and Armando take, you need to write down the given and solve them with the given solution.

David – 15 reports

Armando – 37 reports

Total Reports = 52 reports in total

Total Reports in an hour = 52

Overall total reports = 400

Time to finish = ?

If you try to evaluate, if you have 50 reports in an hour with a total of 400 reports, you could have gain 8 hours by doing the reports.

So to expand more, 52 reports will be divided into 400, giving a total of 7.6

<span>So the answer is that they will take 7 hours and a half in doing the reports.</span>

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egoroff_w [7]

Answer:

The slope of a linear function. The steepness of a hill is called a slope. The same goes for the steepness of a line. The slope is defined as the ratio of the vertical change between two points, the rise, to the horizontal change between the same two points, the run.

Step-by-step explanation:

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There is an integer n such that 2n2 − 5n + 2 is prime. To prove the statement it suffices to find a value of n such that (n, 2n2
fomenos

Answer:

n = 0 or 3

Step-by-step explanation:

2n² - 5n + 2

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Which equation combines with the given equation to form a system of equations with the solution x = 3 and y = 9? x + 2y = 21
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Alexis wanted to understand whether grade level had any relationship to their opinion on extending the school day. She surveyed
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Actually there is enough information to solve this problem. First, let us find the total per row and per column.


 (see attached pic)


P(Grade 10 | opposed) with P(opposed | Grade 10)

P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)

P(Grade 10 | opposed) = 13 / 41 = 0.3171

 

P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)

P(opposed | Grade 10) = 13 / 32 = 0.4063

 

Therefore:

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Answer:

P(Grade 10 | opposed) < P(opposed | Grade 10)

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Given that the basket of watermelons sells for $9 before tax and the tax rate is 9%.

The tax on the basket of watermelons is given by

\frac{9\%}{100\%} \times\$9=0.09\times\$9 \\  \\ =\$0.81

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