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zhannawk [14.2K]
2 years ago
4

A man 2m high observes the angle of elevation to the top of a building to be 61 degrees, and the angle of depression to the bott

om of the building to be 18 degrees. How tall is the building?

Mathematics
1 answer:
Anni [7]2 years ago
3 0
I've included a picture to illustrate.

We can see from the picture that we need to find side X of the triangle to be able to find side Y of the building.
tan18= \frac{2}{X} \\ X= \frac{2}{tan18} \\ X=6.16 m

Now just find side Y:
tan61=\frac{Y}{6.16}\\ 6.16tan61=Y\\ 11.11m=Y

Don't forget to add 2 m to 11.11 m for the total height of the building.

13.11 m is the height of the building.

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Rammy has $9.60 to spend on some peaches and a gallon of milk. Peaches
sergeinik [125]

Answer:

\large \boxed{\text{5.00 lb}}

Step-by-step explanation:

\begin{array}{rcl}1.20x + 3.60 & \leq & 9.60\\1.20x & \leq & 6.00\\x &\leq & \mathbf{5.00}\\\end{array}\\\text{Rammy can buy $\large \boxed{\textbf{5.00 lb}}$ of peaches.}

Check:

\begin{array}{rcl}1.20(5.00) + 3.60 & \leq & 9.60\\6.00 + 3.60 & \leq & 9.60\\9.60 & \leq & 9.60\\\end{array}

OK.

5 0
2 years ago
The average weight of a chicken egg is 2.25 ounces with a standard deviation of 0.2 ounces. You take a random sample of a dozen
n200080 [17]

Answer:

P(\bar X

P(\bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent interest on this case, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(2.25,\frac{0.2}{\sqrt{12}})

Solution to the problem

We want this probability:

P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X

P(\bar X

5 0
2 years ago
Mustafa, Heloise, and Gia have written more than a combined total of 2222 22 articles for the school newspaper. Heloise has writ
Papessa [141]

Answer: m>8

Mustafa could have written more than 8 articles for the newspaper.

Step-by-step explanation:

Given: Heloise has written 1/4 as many articles as Mustafa has. Gia has written 3/2 as many articles as Mustafa has.

Let m be the number of articles Mustafa writes.

Then articles written by Heloise=\frac{1}{4}m

And articles written by Gia=\frac{3}{2}m

The total number of articles =m+\frac{1}{4}m+\frac{3}{2}m=\frac{4m+m+6m}{4}=\frac{11m}{4}

Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

\frac{11m}{4}>22\\\Rightarrow\ m>\frac{22\times4}{11}\\\Rightarrow\ m>8

Hence, Mustafa could have written more than 8 articles for the newspaper.

3 0
2 years ago
Read 2 more answers
On Thursday, Movietown Theater made 4/5 of their popcorn with butter. The remaining , 35.2 ounces was made without butter. How m
Y_Kistochka [10]
35.2 ounces is 1/5 of the popcorn

so 35.2 x 5 = 176

1 pound = 16 ounces 

176÷16=11

The movie theater made 11 pounds of popcorn
3 0
2 years ago
Read 2 more answers
Your tutor asks you to record the time you spend using IT during the week. You have recorded this time below: Day Time Monday 0.
NikAS [45]

Let us convert all figures into decimals so that we can compare them easily.

Monday    0.3

Tuesday   15% = 0.15

Wednesday   1/6 = 0.1666

Thursday   0.2

Friday   1/8 = 0.125

Clearly, I spent the least amount of time on Friday using IT and the time is 0.125 or 1/8.


7 0
2 years ago
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