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loris [4]
2 years ago
12

Cells pass through a G2 checkpoint before entering mitosis. Ideally, if DNA damage is 2 detected, the cells do not enter mitosis

until the damage is repaired. Why is DNA damage repaired before cells enter mitosis? *
A.) So that another round of DNA synthesis does not have to take place

B.) So that the chromosomes can align at the metaphase plate during mitosis

C.) So that the cytoplasm can be divided equally between the two daughter cells

D.)So that healthy daughter cells are produced, allowing the organism to continue growing
Biology
1 answer:
galina1969 [7]2 years ago
4 0
I think that the answer is D. The cell employs the G2 checkpoint to check for DNA damage and completeness of DNA replication. This is done to ensure that cell division runs smoothly which means that healthy daughter cells, with complete and undamaged DNA, will be produced. At this point, all necessary repairs are applied.  
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Show how selection, genetic drift, gene flow, and mutation relate to genetic variation. Match the words in the left column to th
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Answer:

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2. Selection- may increase, decrease or maintain genetic variation

3. Genetic drift- decrease genetic variation.

4. Gene flow- may increase or decrease genetic variation

Explanation:

1. A mutation refers to the changes in the DNA in an organism. The mutation of genes in DNA produces new adaptive features to evolve which increases the genetic variation of the organisms.

2. The natural selection favors the species which are best suited to live in that natural conditions. The natural selection, therefore, may increase or decrease the variation in a population.

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8 0
2 years ago
Streptomycin is extracted from the fermentation broth using an organic solvent in a counter-current staged extraction unit. The
amid [387]

Answer:

6.75l l/min

Explanation:

Streptomycin is extracted  from the fermentation broth using an organic solvent in a counter current staged extraction unit.

for 5 stage counter current staged extraction unit for streptomycin

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X0 = 10.0g/l

X5/X0 = 0.02

given

Xn/X0, E, and

n = 5

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A and C

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