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2 years ago

Add and simplify 9/16=1/2=what

2 answers:

6 0

9 / 16 + 1/2 = ?

Step 1. In adding fractions, denominators must be the same. As we can see the denominators are 16 and 2. We observe that 16 is 8 times bigger than 2. Therefore, we must multiply 1/2 by 8 to get the same denominator.

(1 * 8) / (2 * 8) = 8 / 16

Step 2. Add the numerators and put them over the same denominator.

9/16 + 8/16 = (9+8) / 16 = 17 / 16

Step 3. Simplify the fractions. (If needed)

As you can see, 17/16 is in its simplest form. Thus, 9/16 + 1/2 = 17/16

Andru [333]2 years ago

3 0

If you would like to add and simplify 9/16 and 1/2, you can calculate this using the following steps:

9/16 + 1/2 = 9/16 + 8/16 = (9 + 8) / 16 = 17/16 = 1 1/16

The correct result would be 1 1/16.

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What two whole numbers is the quotient between 37 divided by 6

Nitella [24]

Answer:

6 and 7

Step-by-step explanation:

To do this, we need to look at the two closest numbers that are divisible by 6. These are 36 and 42.

$36/6=6\\42/6=7$

As 37 is between 36 and 42, the quotient must be between 6 and 7

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2 years ago

Tyrone paid $234.33 for a new watch, after tax, and the tax rate is 7%. What was the original price of the watch?

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The cost of the watch originally cost $1,640.31

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2 years ago

The slope of a line is 2. The y-intercept of the line is -6. Which statements accurately describe how to graph the function

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It’s a. Start at the y intercept and rise over run to the next point.

8 0

2 years ago

A steel pipe 100 cm long has an outside diameter of 2 cm and an inside diameter of 1.8 cm. If thee density of the steel is 7.8 g

ELEN [110]

Answer:

The mass of the pipe is $465\ g$

Step-by-step explanation:

step 1

Find the volume of the steel pipe

The volume is equal to the area of outside circle minus the area of inside circle, multiplied by the length of the pipe

$V=\pi [r2^{2}-r1^{2}]L$

we have

$r2=2/2=1\ cm$ ---> the radius is half the diameter

$r1=1.8/2=0.9\ cm$ ---> the radius is half the diameter

$L=100\ cm$

$\pi=3.14$

substitute

$V=(3.14)[1^{2}-0.9^{2}](100)=59.66\ cm^{3}$

step 2

Find the mass

The mass is equal to the density multiplied by the volume

$m=7.8(59.66)=465\ g$

8 0

2 years ago

In professional basketball games during 2009-2010, when Kobe Bryant of the Los Angeles Lakers shot a pair of free throws, 8 time

ziro4ka [17]

Answer:

Is plausible that the successive throws are independent

Step-by-step explanation:

1) Table with info given

The observed values are given by the following table

__________________________________________________

First shot Made Second shot missed Total

__________________________________________________

Made 152 33 185

Missed 37 8 45

__________________________________________________

Total 189 41 230

2) Calculations and test

We are interested on check independence and for this we need to conduct a chi square test, the next step would be find the expected value:

Null hypothesis: Independence between two successive free throws

Alternative hypothesis: No Independence between two successive free throws

_____________________________________________________

First shot Made Second shot missed

_____________________________________________________

Made 189(185)/230=152.0217 41(185)/230=32.9783

Missed 189(45)/230=36.9783 41(45)/230=8.0217

_____________________________________________________

On this case all the expected values are higher than 5 and the sample size 230 is enough to apply the chi squared test.

3) Calculate the chi square statistic

The statistic for this case is given by:

$\chi_{cal}^2 =\sum \frac{(O_i -E_i)}{E_i}$

Where O represent the observed values and E the expected values. Replacing the values that we got we have this

$\chi_{cal}^2 =\frac{(152-152.0217)^2}{152.0217}+\frac{(33-32.9783)^2}{32.9783}+\frac{(37-36.9783)^2}{36.9783}+\frac{(8-8.0217)^2}{8.0217}=0.000003098+0.00001428+0.00001273+0.0.00005870=0.00008881$

Now with the calculated value we can find the degrees of freedom

$df=(r-1)(c-1)=(2-1)(2-1)=1$ on this case r means the number of rows and c the number of columns.

Now we can calculate the p value

$p_v =P(\chi^2 >0.00008881)=0.9925$

On this case the pvalue is a very large value and that indicates that we can fail to reject the null hypothesis of independence. So is plausible that the successive throws are independent.

5 0

2 years ago