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alekssr [168]
2 years ago
6

A mirror with a parabolic cross section is used to collect sunlight on a pipe located at the focus of the mirror. The pipe is lo

cated 8 inches from the vertex of the mirror. Write an equation of the parabola that models the cross section of the mirror. Assume that the parabola opens upward.
Mathematics
1 answer:
vodomira [7]2 years ago
3 0

Answer: x^2=32y


Step-by-step explanation:

Given:  A mirror with a parabolic cross section is used to collect sunlight on a pipe located at the focus of the mirror.

The pipe is located 8 inches from the vertex of the mirror.

Assume the vertex is at the origin.

If the parabola opens upwards

then the coordinates of focus= (0,8)

We know that equation of parabola with focus (0,a) and open upards is of the form (vertex=(0,0)) is

x^2=4ay

Substitute the value of a=8 in equation, we get

x^2=4\times8y

\Rightarrow\ x^2=32y

Therefore, equation of the parabola that models the cross section of the mirror is x^2=32y

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Answer:

1.5 mph

Step-by-step explanation:

Let speed of boat be x

let speed of current be c

Also, note D = RT

D is distance

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(x+c)3 = D

And for second leg , we can write:

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7.8c = 1.8x

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A building has an entry the shape of a parabolic arch 84 ft high and 42 ft wide at the base, as shown below. A parabola opening
Gala2k [10]
Since the parabola passes by the center its equation is:

y = ax². But it opens downward, that means the coefficient a is negative.

Then the equation becomes:

y = - ax², with x = 0 as its axis of symmetry.

We are given that the height is 84 ft when the opening downward is 42 ft.
That means to the (height) y, corresponds x =+21 & x=-21 (due to symmetry).
In order to calculate a let's plug y & x with their related values:

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2 years ago
A teacher decides to purchase a new car and considers two options. Option one is the new Zoomba for $60,000 with an expected dep
kupik [55]

Answer:

She chose Option 2 which is a linear option, because it offers a smaller lose    

in value compared to option 1 which is an exponential option.

The final value for option 2=$32,800

Step-by-step explanation:

Option 1

New Zoomba for 60000 with a depreciation rat of 2%per month for 3 years

Exponential equation;

y=a(1-r)^t

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y=future value

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r=depreciation rate=2% per month

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Replacing;

y=60000(1-2/100)^36

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The value after 3 years=$28,992.79

Initial value-Final value=(60000-28992.79)=$31007.21

Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100

(31007.21/60000)×100=51.68%

Option 2

New starfish for $40,000 with a depreciation of $200 per month for 3 years

Linear equation;

y=a-bt

where;

y=Future value

a=Initial value=$40,000

b=the depreciation amount per time interval=$200 per month for 3 years

t=time interval=(3×12)=36 months

Replacing;

y=40000-(200×36)

y=32,800

Final value=y=$32,800

Initial value-Final value=(40000-32800)=$7200

Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100

(7200/40000)×100=18%

Option 1(51.68%)>Option 2(18%) therefor Option 1 loses value at a faster rate than Option 2

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in value compared to option 1 which is an exponential option

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