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dedylja [7]
2 years ago
12

Instructions:Type the correct answer in the box. Use numerals instead of words. Mason conducted a survey of his class to determi

ne if they prefer to use pens or pencils for their math homework. Out of the 30 students in his class, 12 of them are male. A total of 21 students said they prefer pencils, and 12 of those students are female. Fill in the missing joint and marginal frequencies in the table. Pencils Pens Total Male % 10% 40% Female % 20% % Total 70% % 100%

Mathematics
2 answers:
BartSMP [9]2 years ago
3 0
Here's your table, more or less.

Mila [183]2 years ago
3 0

Answer:

The answer in the picture

Step-by-step explanation:

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On a certain​ route, an airline carries 7000 passengers per​ month, each paying ​$30. A market survey indicates that for each​ $
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Answer:

The ticket price that maximizes revenue is $50.

The maximum monthly revenue is $250,000.

Step-by-step explanation:

We have to write a function that describes the revenue of the airline.

We know one point of this function: when the price is $30, the amount of passengers is 7000.

We also know that for an increase of $1 in the ticket price, the amount of passengers will decrease by 100.

Then, we can write the revenue as the multiplication of price and passengers:

R=p\cdot N=(30+x)(7000-x)

where x is the variation in the price of the ticket.

Then, if we derive R in function of x, and equal to 0, we will have the value of x that maximizes the revenue.

R(x)=(30+x)(7000-100x)=30\cdot7000-30\cdot100x+7000x-100x^2\\\\R(x)=-100x^2+(7000-3000)x+210000\\\\R(x)=-100x^2+4000x+210000\\\\\\\dfrac{dR}{dx}=100(-2x)+4000=0\\\\\\200x=4000\\\\x=4000/200=20

We know that the increment in price (from the $30 level) that maximizes the revenue is $20, so the price should be:

p=30+x=30+20=50

The maximum monthly revenue is:

R(x)=(30+x)(7000-100x)\\\\R(20)=(30+20)(7000-100\cdot20)\\\\R(20)=50\cdot5000\\\\R(20)=250000

3 0
2 years ago
Vineet solved a system of equations by substitution. In his work, he substituted an expression for one of the variables and solv
mezya [45]
Vineet can conclude that:
B ) the system of equations does not have a solution.
10 0
2 years ago
Read 2 more answers
A textbook store sold a combined total 402 of psychology and math textbooks in a week. The number of psychology textbooks sold w
uranmaximum [27]

Answer:

The number of textbooks of each type were sold is <u>134 math </u>and <u>268 psychology </u>books.

Step-by-step explanation:

Given:

Total number of math and psychology textbooks sold in a week is 402.

Now, let the number of math textbooks sold be x.

And, the number of psychology textbooks be 2x.

According to question:

x+2x=402

3x=402

Dividing both sides by 3 we get:

x=134

So, total number of math textbooks were 134 .

And, total number of psychology textbooks were 2x=2\times 134

                                                                                 =268.

Therefore, the number of textbooks of each type were sold is 134 math and 268 psychology books.

4 0
2 years ago
The graphs below show measurements from cubes with different side lengths. Which pairs of variables have a linear relationship?
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Answer:

side length and perimeter of 1 face

area of 1 face and surface area

Step-by-step explanation:

Just did it

4 0
2 years ago
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Using the U- Substitution u=sqrt(2x), integral form 2-8 dx/ sqrt(2x) + 1 is equivalent to ...
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We will use u-substitute:u= \sqrt{2x} , \frac{du}{dx}= \frac{1}{ \sqrt{2x} }= \frac{1}{u}Then for substitution:dx=u du. and integral becomes:\int { \frac{u}{u+1} } \, du = \int { \frac{u+1-1}{u+1} } \, du= \int{1} \, du- \int { \frac{1}{u-1} } \, dx=u-ln(u+1)=\sqrt{2x}-ln( \sqrt{2x}+1). Now we will change the values of limits: \sqrt{16}-ln( \sqrt{16}+1)-( \sqrt{4}-ln( \sqrt{4}+1))=4-ln(5)-2+ln(3)=2+ln(0,6)=2-0.51=1.49

8 0
2 years ago
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