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2 years ago

The radius of circle G is 4 cm. What is the tangent

1 answer:

4 0

The tangent of a given circle is perpendicular to the radius a the point called point if tangency. The radius of the circle is perpendicular to the tangent at the point of tangency. This property is especially useful in cases where the radius that connects to the point of tangency forms a part of right angle because the pythagorean theorem and trigonometry apply to right angles.

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there are two pizzas. conor ate 1⁄4 of a pizza, brandon 2⁄8, tyler 3⁄4, and audrey 4⁄8. who ate the most of the two pizzas? a. a

Sindrei [870]

The best way to determine which among the fractions has the greatest value, convert all of them to their decimal equivalents. To do so, divide the numerator by the denominator. Conor ate 0.25 of the pizza, Brandon also 0.25, Tyler 0.75, and Audrey 0.5. Thus, the answer is letter "B. Tyler".

7 0

1 year ago

Read 2 more answers

Find the volume of a pyramid 5 yards tall if the base is a rectangle 15 feet by 6 feet.

BaLLatris [955]

V=lwh/3=5*15*6/3=160

3 0

2 years ago

Read 2 more answers

Choose the option that best completes the statement below. In finding the number of permutations for a given number of items, __

vodomira [7]

Let’s look at the permutations of the letters “ABC.” We can write the letters in any of the following ways:
ABC
ACB
BAC
BCA
CBA
CAB
Since there are 3 choices for the first spot, two for the next and 1 for the last we end up with (3)(2)(1) = 6 permutations. Using the symbolism of permutations we have: $3 P_{3}=(3)(2)(1)=6$ . Note that the first 3 should also be small and low like the second one but I couldn’t get that to look right.

Now let’s see how this changes if the letters are AAB. Since the two As are identical, we end up with fewer permutations.
AAB
ABA
BAA
To make the point a bit better let’s think of one A are regular and one as bold A.
ABA and ABA look different now because we used bold for one of the As but if we don’t do this we see that these are actual the same. If they represented a word they would be the same exact word.

So in this case the formula would be $\frac{3 P_{3} }{2!}= \frac{(3)(2)(1)}{(2)(1)}= \frac{6}{2}=3$ . We use 2! In the denominator because there are 2 repeating letters. If there were three we would use 3!

Hopefully, this is enough to let you see that the answer is A. The number of permutations is limited by the number of items that are identical.

7 0

1 year ago

Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac

melomori [17]

Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ $b+c=20$
Equation [2] ⇒ $1.50b+5c=54.50$

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; $b$ and $c$ , that we need to solve, then this becomes a simultaneous equation problem.

First, rearrange Equation [1] to make either $b$ or $c$ the subject:
$b+c=20$
$b=20-c$

Then we substitute $b=20-c$ into Equation [2]
$1.50b+5c=54.50$
$1.50(20-c)+5c=54.50$
$30-1.50c+5c=54.50$
$5c-1.5c=54.50-30$
$3.5c=24.50$
$c=7$

Now we know the value of $c$ which is $c=7$ , substitute this value into $b=20-c$ we have $b=20-7=13$

Answer:
Numbers of books = 13
Numbers of CDs = 7

5 0

2 years ago

You take the four Aces, four $2$'s, and four $3$'s from a standard deck of 52 cards, forming a set of $12$ cards. You then deal

kap26 [50]

Answer:

Probability each player gets an ace, a $2 and a $3 = 0.0374

Step-by-step explanation:

The total number of ways to divide the card in triples among four players = 369600 ways

The total number of ways to share the cards such that no card is repeated in each triple = 13824 ways

Probability each player gets an ace, a $2 and a $3 = 13824/369600

Probability each player gets an ace a $2 and a $3 = 0.0374

Note: Further explanation is provided in the attachment.

8 0

1 year ago