Question

The means and mean absolute deviations of monthly snowfall during the winter months in two cities are shown in the table below.

Answer 1

Answer:

The correct option is D

Step-by-step explanation:

From the given table it is clear that the mean of north town is 8.9 inches and the mean of south town be 6.3.

The difference of the means is

$D=8.9-6.3=2.6$

Let the difference between the means is about k times the mean absolute deviation of the data sets.

$k(0.55)=2.6$

$k=\frac{2.6}{0.55}=4.7272...\approx 5$

$k(0.48)=2.6$

$k=\frac{2.6}{0.48}=5.4166667\approx 5$

Therefore the difference between the means is about 5 times the mean absolute deviation of the data sets. Hence the correct option is D.

Answer 2

Answer:

Option D.

Step-by-step explanation:

Given information:

Mean of north town =  8.9 inches

Mean of south town = 6.3 inches

Mean absolute deviation of north town = 0.55 inches.

Mean absolute deviation of south town = 0.48 inches.

The difference of the means of both towns is

$8.9-6.3=2.6$

Let the difference between the means is about k₁ times the mean absolute deviation of the data sets 1 .

$k_1(0.55)=2.6$

$k_1=\frac{2.6}{0.55}=4.7272..\approx 5$

Let the difference between the means is about k₂ times the mean absolute deviation of the data sets 2 .

$k_2(0.48)=2.6$

$k_2=\frac{2.6}{0.48}=5.4166..\approx 5$

The difference between the means is about 5 times the mean absolute deviation of the each data sets.

Therefore, the correct option is D.