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Semmy [17]
2 years ago
8

While cruising at a steady speed of 400 km/h, you identify a storm cloud straight ahead 45 km away. To avoid turbulence, you sta

rt climbing at an angle of elevation of 15°. If you maintain this speed and direction for 6 min, how far will you be from the storm
Mathematics
1 answer:
ryzh [129]2 years ago
5 0
First calculate distance traveled after 6 min.
400 * (6/60) = 400*(1/10) = 40 km

Next, draw triangle with 2 sides being 45 and 40. The included angle between these sides is 15, the angle of elevation. The third side is distance from plane to storm cloud.

Next, use Law of cosines to find distance.
d = sqrt(40^2 + 45^2 - 2(40)(45)cos(15))

d = 12.152 km
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Answer:

EH = 3.31

Step-by-step explanation:

We have been given a right angle triangle EKL. As KH has been given as the altitude (perpendicular) of the right angled triangle, and K is the right angle, we can say that EK is tthe base of the triangle and EH is the only side lleft, which is the hypotenuse of the triangle.

Where,

EK = Base = 3

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m<E = 25

We know that

cosθ = Base/ Hypotenuse

cos 25 = 3/ EH

EH = 3/cos25

EH = 3.31

Perpendicular alitutude can also be calculated by using the formula for tanθ.

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2 years ago
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Step-by-step explanation:

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1 year ago
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Dominic runs a farm stand that sells peaches and grapes yesterday Dominic sold 34 pounds of peaches and 45 lb of grapes for a to
iren2701 [21]

Answer:34p+16g=208

47p+16g=208

Step-by-step explanation:

Let p=the price of each pound of peaches.

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0.35+0.2+.25
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