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seraphim [82]
2 years ago
10

Consider quadrilateral LMNO. If quadrilateral LMNO is a parallelogram, what must the measure of angle LMN be? m∠LMN = °

Mathematics
2 answers:
koban [17]2 years ago
6 0
The correct answer is 105 
wolverine [178]2 years ago
5 0

Answer:

105 is the correct answer

Step-by-step explanation:


You might be interested in
Jennifer can run 12 miles in 2 hours, and she can bike 33 miles in 3 hours. What is Jennifer’s biking speed?
anastassius [24]

Answer:

11 miles per hour

Step-by-step explanation:

The biking speed is found by taking the miles and dividing by the hours

33 miles/ 3 hours

11 miles per hour

3 0
2 years ago
According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m
tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

x/4 = 0.25x of 1/5 = 0.2(very active). So

P(A) = 0.8x + 0.25*0.2x = 0.85x

Probability of developing diabetes while being very active:

0.25x of 0.2. So

P(A \cap B) = 0.25x*0.2 = 0.05x

What is the probability that a middle-aged man with diabetes is very active?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.05x}{0.85x} = \frac{0.05}{0.85} = 0.0588

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

4 0
2 years ago
Given directed line segment QS , find the coordinates of R
Degger [83]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, what are the coordinates of point Q and R. But I would show how to solve this.

The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at (x_1,y_1) and B(x_2,y_2) is given by the formula:

x=\frac{a}{a+b}(x_2-x_1)+x_1\\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1

If point Q is at (x_1,y_1) and S at (x_2,y_2)  and R(x, y) divides QS in the ratio QR to RS is 3:5, The coordinates of R is:

x=\frac{3}{3+5}(x_2-x_1)+x_1=\frac{3}{8}(x_2-x_1)+x_1\\ \\y=\frac{3}{3+5}(y_2-y_1)+y_1=\frac{3}{8}(y_2-y_1)+y_1

Let us assume Q(−9,4) and S(7,−4)

x=\frac{3}{8}(7-(-9))+(-9)=\frac{3}{8}(16)-9=-3\\\\y=\frac{3}{8}(-4-4)+4=\frac{3}{8}(-8)+4=1

4 0
2 years ago
The random variable X is normally distributed with mean 82 and standard deviation 7.4. Find the value of q such that P(82 − q &l
mezya [45]
P(82 - q < x < 82 + q) = 0.44
P(x < 82 + q) - P(82 - q) = 0.44
P(z < (82 + q - 82)/7.4 - P(z < (82 - q - 82)/7.4) = 0.44
P(z < q/7.4) - P(z < -q/7.4) = 0.44
P(z < q/7.4) - (1 - P(z < q/7.4) = 0.44
P(z < q/7.4) - 1 + P(z < q/7.4) = 0.44
2P(z < q/7.4) - 1 = 0.44
2P(z < q/7.4) = 1.44
P(z < q/7.4) = 0.72
P(z < q/7.4) = P(z < 0.583)
q/7.4 = 0.583
q = 0.583 x 7.4 = 4.31
8 0
2 years ago
An accident at an oil drilling platform is causing a circular-shaped oil slick to form. The volume of the oil slick is roughly g
Basile [38]

Answer:

V(t)=0.0112\pi t^{2}

Step-by-step explanation:

we have

V(r)=0.07\pi r^{2} -----> equation A

r(t)=0.4t -----> equation B

To find out (V of r)(t) substitute equation B in equation A

V(r(t))=V(t)

V(t)=0.07\pi (0.4t)^{2}

V(t)=0.07\pi (0.16)t^{2}

V(t)=0.0112\pi t^{2}

3 0
2 years ago
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