Question

Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula? Quadratic formula: x =

Answer 1

Hello : 
the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions
in this exercice : -3x²-2x+6 =0.....a = -3   b = -2     c =6
calculate : Δ............................

Answer 2

Answer:

$x=\frac{2\pm\sqrt{76}}{-6}$

Step-by-step explanation:

Given : Equation $-3x^2-2x+6=0$

To find : The correct substitution of the the values a, b, and c from the equation into quadratic formula?

Solution :

The general form of the quadratic equation is $ax^2+bx+c=0$

Where, a is the coefficient of $x^2$

b is the coefficient of x

c is the constant term.

On comparing with  $-3x^2-2x+6=0$

a=-3 , b=-2 , c=6

The quadratic formula of the quadratic equation is given by,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substituting the values,

$x=\frac{-(-2)\pm\sqrt{(-2)^2-4(-3)(6)}}{2(-3)}$

$x=\frac{2\pm\sqrt{4+72}}{-6}$

$x=\frac{2\pm\sqrt{76}}{-6}$

So, The required formula which shows the correct substitution of the values.