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Rashid [163]
2 years ago
4

In a bakery, the number of buns delivered is a function of the number of boxes packed. What is the domain of this function?

Mathematics
2 answers:
ELEN [110]2 years ago
7 0
Domain only includes positive in real numbers only

vichka [17]2 years ago
6 0
How many buns are in the box and how many boxes you have
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In which diagram are angles 1 and 2 vertical angles?
Solnce55 [7]

<u>Answer</u>

First diagram shows  1 and 2 vertical angles

<u>Explanation</u>

From the all four diagrams,we get the diagram first shows the vertically opposite angles.  

angle 1 and angle 2 are vertically opposite angles

vertically opposite angles are equal in measurements. when two lines are intersect each other form four angles, out of this four angles two pairs of vertically opposite  angles are there.

All other figures  angle 1 and 2 shows adjacent angles.

6 0
2 years ago
Read 2 more answers
The nakagin capsule tower has 140 modules and is 14 stories high if the modules were divided evenly among the number of stories
Burka [1]
To determine the number of modules that is in each story, we simply divide the number of modules by the number of stories. 
                           = 140 / 14
Simplifying,
                           = 10 modules / story
Therefore, by even distribution we note that there are 10 modules per story. 
5 0
2 years ago
Anna’s bank gives her a loan with a stated interest rate of 10.22%. How much greater will Anna’s effective interest rate be if t
nata0808 [166]
If the interest rate is compounded daily, we have the effective interest rate calculated as:
r = (1 + 0.1022/30)^30 -1
r = 0.1074 or 10.74%

Therefore, the effective interest rate if the compounded daily rather than monthly is 10.74-10.22 = 0.52 points higher.

8 0
2 years ago
What fraction of 30 is 12
zloy xaker [14]

Call the mystery fraction ' F ' (for 'fraction').

12 is the mystery fraction of 30 .

                                             12  =  F x 30

Divide each side by  30 :      F  =  12/30  =  2/5 .

5 0
2 years ago
Square $ABCD$ has area $200$. Point $E$ lies on side $\overline{BC}$. Points $F$ and $G$ are the midpoints of $\overline{AE}$ an
Charra [1.4K]

1. Consider square ABCD. You know that  

A_{ABCD}=AD^2=200,

then

AB=BC=CD=AD=10\sqrt{2}.

2. Consider traiangle AED. F is mipoint of AE and G is midpoint of DE, then FG is midline of triangle AED. This means that

FG=\dfrac{AD}{2}=\dfrac{10\sqrt{2} }{2}=5\sqrt{2}.

3. Consider trapezoid BFGC. Its area is

A_{BFGC}=\dfrac{FG+BC}{2}\cdot h, where h is the height of trapezoid and is equal to half of AB. Thus,

A_{BFGC}=\dfrac{FG+BC}{2}\cdot \dfrac{AB}{2}=\dfrac{5\sqrt{2}+10\sqrt{2}}{2}\cdot \dfrac{10\sqrt{2}}{2}=75.

4.

A_{BFGC}=A_{BFGE}+A_{EGC},\\A_{EGC}=A_{BFGC}-A_{BFGE}=75-34=41.

5. Note that angles EGC and CGD are supplementary and

\sin \angle CGD=\sin \angle EGC.

Then

A_{CGD}=\dfrac{1}{2}CG\cdot CD\cdot \sin \angle CGD=\dfrac{1}{2}CG\cdot EG\cdot \sin \angle CGE=A_{ACG}=41.

Answer: A_{CGD}=41.

8 0
2 years ago
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