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kirill115 [55]
2 years ago
10

What is Discount Comics is running a special: 20 comics for $5.00. Seth purchases 30 comics for $7.50. What is the sale price pe

r comic?
$ per comic?
What is the constant of proportionality?
Mathematics
2 answers:
Shalnov [3]2 years ago
8 0
Since we are finding the unit rate of the cost per comic, we will need to divide $5 by 20 comics which you will get 0.25 cents and divide $7.50 by 30 comics which you will also get 0.25 cents.Therefore, the unit rate and constant of proportionality is 0.25 cents.
Rom4ik [11]2 years ago
6 0

Answer:

1# 0.25 2# 0.25

Step-by-step explanation:

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Find the sum of the first 63 terms of –19, -13, -7 …
boyakko [2]

The Given Sequence is an Arithmetic Sequence with First term = -19

⇒ a = -19

Second term is -13

We know that Common difference is Difference of second term and first term.

⇒ Common Difference (d) = -13 + 19 = 6

We know that Sum of n terms is given by : S_n = \frac{n}{2}(2a + (n - 1)d)

Given n = 63 and we found a = -19 and d = 6

\implies S_6_3 = \frac{63}{2}(2(-19) + (63 - 1)6)

\implies S_6_3 = \frac{63}{2}(-38 + (62)6)

\implies S_6_3 = \frac{63}{2}(-38 + 372)

\implies S_6_3 = \frac{63}{2}(-38 + 372)

\implies S_6_3 = \frac{63}{2}(334)

\implies S_6_3 = {63}(167) = 10521

The Sum of First 63 terms is 10521

4 0
2 years ago
Seams Personal advertises on its website that 95% of customer orders are received within four working days. They performed an au
Bezzdna [24]

Answer:

a. Yes(n=500>=5, n(1-p)=25>=5)

b. 0.15241

Step-by-step explanation:

a. A normal approximation to the binomial can be used  n\geq5 and n(1-p)>=5:

#We calculate our p as follows:

\hat p=x/n=470/500=0.94

n=500

n(1-p)=500(1-0.95)=25

Hence, we can use the normal approximation.

b. This is a normal approximation.

-Given that p=0.95(95%)

-We verify if our distribution can be approximated to a normal:

np=0.95\times 500=475\\n(1-p)=500(1-0.95)=25\\\\np\geq 5,\ n(1-p)\geq 5

Hence, we can use the normal approximation of the form:

P_{bin}(k,n,p)->N(\mu,\sigma^2)\left \{ {{\mu=np=475} \atop {\sigma=\sqrt{np(1-p)}=4.8734}} \right. \\\\\\P_{bin}(k\leq 470)\approx P_{norm}(x\leq 470.5)=P_{norm}(z\leq \frac{470-475}{4.8734})\\\\P_{norm}(z\leq -1.0260)=0.15241

Hence, the probability of the sample proportion  is the same as the proportion of the sample found is 0.15241

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2 years ago
The Graduate Record Examination and the Miller’s Analogy Test are generally used for _______________.
kicyunya [14]

Answer:

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Step-by-step explanation:

The graduate record examination is a standard test for the selection process of graduate schools and is a requirement. It tests the abstract thinking is areas of analytical writing, mathematics and vocabulary.

The millers analogy test is used for graduate school admissions and admissions to high IQ institutions. It is a verbal or computer based assessment aiming to test the individuals logical and analytical skills by using partial analogies.

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