Answer:
Darnell can read 1,715 words in 7 minutes
Step by step Explanation:
1. I need to find out how many words he reads in 1 minute. Divide 735 by 3, my answer is 245
245
______
3)735
6 bring down the 3 to make 13
-_____
1 3
12 bring down the 5 to make 15
-______
1 5
15
___________
0
2. multiply 735 by 2 cause he reads 735 words in 3 minutes and we are tryna find out how many words he reads in 7 minutes. 3×2=6, so 735+735 (735×2) equals 1470
3. Add 245, for that extra minute that we missed. my answer is 1,715 words in 7 minutes
There's not enough given information in the question to calculate an answer.
If we only know that the volume of the box is 96 cm³, then there are an infinite
number of different lengths, widths, and surface areas that it could have.
Answer:
Step-by-step explanation: if Peytons base pay= $60 plus she earns commission on $x (computers sold)
P= $60+ (0.025x)
You would multiply by 0.025 as this equals 2.5%
Remember PEMDAS- parentheses, exponents, multiplications, division, addition, subtraction
Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
