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damaskus [11]
2 years ago
13

JL is a diameter of circle K. If tangents to circle K are constructed through points L and J, what relationship would exist betw

een the two tangents? Explain.
Mathematics
1 answer:
Sergeu [11.5K]2 years ago
6 0
I. Let t be the line tangent at point J. We know that a tangent line at a  point on a circle, is perpendicular to the diameter comprising that certain point.
So t is perpendicular to JL

let l be the tangent line through L. Then l is perpendicular to JL
 
ii. So t and l are 2 different lines, both perpendicular to line JL.

2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.

Remark. Draw a picture to check the steps
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Answer:

It would be A, or the first graph

Step-by-step explanation:

So we’ve now created an equation

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dolphi86 [110]

Answer:

Correct choice is B

Step-by-step explanation:

All given options represent quadratic function. Let the equation of this quadratic function be

f(x)=ax^2+bx+c.

Then

1. f(0)=2=a\cdot 0^2+b\cdot 0+c\Rightarrow c=2;

2. f(1)=7.5=a\cdot 1^2+b\cdot 1+c\Rightarrow 7.5=a+b+2;

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Solve the system of two equations:

\left\{\begin{array}{l}a+b+2=7.5\\4a+2b+2=12\end{array}\right.\Rightarrow\left\{\begin{array}{l}a=5.5-b\\4(5.5-b)+2b=10\end{array}\right.

Then

22-4b+2b=10,\\ \\-2b=-12,\\ \\b=6,\\ \\a=5.5-6=-0.5.

Thus, the equation of the function is

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Note that

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Your grade point average is 3.48. How can you write your grade point average as a fraction?
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Answer:

1). Shifted 2 units right.

2). Shifted 2 units left.

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4). Shifted 2 units down.

Step-by-step explanation:

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2). The curved pit is shifted 2 units left,

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3). The curved pit is shifted  2 units up,

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4). The curved pit is shifted 2 units down,

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