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2 years ago

The team first experiments with changing the position of the curved pit. In the computer program, the

Mathematics

1 answer:

Tju [1.3M]2 years ago

6 0

Answer:

1). Shifted 2 units right.

2). Shifted 2 units left.

3). Shifted 2 units up.

4). Shifted 2 units down.

Step-by-step explanation:

Parent quadratic function is,

y = x²

1). When curved pit of the parent function is shifted 2 units right,

Translated function will be,

y = (x - 2)²

2). The curved pit is shifted 2 units left,

y = (x + 2)²

3). The curved pit is shifted 2 units up,

y = x² + 2

4). The curved pit is shifted 2 units down,

y = x² - 2

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Which graph represents the function f(x) = (x – 5)2 + 3?

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The function
$f(x)=(x-5)^2+3$
describes a parabola with vertex = (5, 3).

The graph of the function is attached.

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Find the equation of the surface. a standard cone with vertex at (6, 0 , 0) opening up on the positive x-axis.

DerKrebs [107]

Solution: Since, it’s a standard cone opening up on the positive x- axis

Therefore, x=√y2+z2

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2 years ago

A process manufactures ball bearings with diameters that are normally distributed with mean 25.1 mm and standard deviation 0.08

marta [7]

Answer:

(a) The proportion of the diameters are less than 25.0 mm is 0.1056.

(b) The 10th percentile of the diameters is 24.99 mm.

(d) The proportion of the ball bearings meeting the specification is 0.8881.

Step-by-step explanation:

Let X = diameters of ball bearings.

The random variable X is normally distributed with mean, μ = 25.1 mm and standard deviation, σ = 0.08 mm.

To compute the probability of a Normally distributed random variable we need to first convert the raw scores to z-scores as follows:

z = (X - μ) ÷ σ

(a)

Compute the probability of X < 25.0 mm as follows:

P (X < 25.0) = P ((X - μ)/σ < (25.0-25.1)/0.08)

= P (Z < -1.25)

= 1 - P (Z < 1.25)

= 1 - 0.8944

= 0.1056

*Use a z-table for the probability.

Thus, the proportion of the diameters are less than 25.0 mm is 0.1056.

(b)

The 10th percentile implies that, P (X < x) = 0.10.

Compute the 10th percentile of the diameters as follows:

P (X < x) = 0.10

P ((X - μ)/σ < (x-25.1)/0.08) = 0.10

P (Z < z) = 0.10

z = -1.282

The value of x is:

z = (x - 25.1)/0.08

-1.282 = (x - 25.1)/0.08

x = 25.1 - (1.282 × 0.08)

= 24.99744

≈ 24.99

Thus, the 10th percentile of the diameters is 24.99 mm.

(c)

Compute the value of P (X < 25.2) as follows:

P (X < 25.2) = P ((X - μ)/σ < (25.2-25.1)/0.08)

= P (Z < 1.25)

= 0.8944

≈ 0.84

*Use a z-table for the probability.

Thus, the ball bearing that has a diameter of 25.2 mm is at the 84th percentile.

(d)

Compute the value of P (25.0 < X < 25.3) as follows:

P (25.0 < X < 25.3) = P ((25.0-25.1)/0.08 < (X - μ)/σ < (25.3-25.1)/0.08)

= P (-1.25 < Z < 2.50)

= P (Z < 2.50) - P (Z < -1.25)

= 0.99379 - 0.10565

= 0.88814

≈ 0.8881

*Use a z-table for the probability.

Thus, the proportion of the ball bearings meeting the specification is 0.8881.

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2 years ago

Which point shows the location of 5 – 2i on the complex plane below? On a coordinate plane, points A, B, C, and D are shown. Poi

Romashka-Z-Leto [24]

Answer:

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Step-by-step explanation:

We have the complex number 5-2i and we have to show the location of the point that represents that number in the complex plane

In the complex plane the real numbers are located in the horizontal axis, increasing to the right. The positives real numbers are at the right of the origin and the negatives to the left.

The complex numbers are located in the vertical axis, with the positives over the origin and the negatives below the origin.

This complex number 5-2i is the sum of a real part (5) and a imaginary part (-2i), so the point will be 5 units rigth on the horizontal axis (for the real part) and 2 units down in the vertical axis (for the imaginary part).

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Artyom0805 [142]

X-intercept has coordinates (x,0)
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