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suter [353]
2 years ago
6

Tasha assembled a picture frame that is advertised as rectangular. The completed frame is 14 inches long and 10 inches wide. She

measured the diagonal length across the frame as 20 inches. Which best explains why the frame cannot actually be rectangular?
Mathematics
2 answers:
murzikaleks [220]2 years ago
5 0

Answer:

A

Step-by-step explanation:

aalyn [17]2 years ago
4 0

the diagonal of a rectangle is square root of (w^2 +l^2)


so square root of (14^2 +10^2) = 17.2 inches

since 20" is longer than 17.2 it can't be a rectangle

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A trapezoid has a base of 4.5 inches, a height of 6 inches, and an area of 21 square inches. The equation below can be used to d
Troyanec [42]

Answer:

b_2 =  -2.5

Step-by-step explanation:

Given

\frac{1}{2}(4.5 + b_2) * 6 = 21

Required

Determine the value of T

\frac{1}{2}(4.5 + b_2) * 6 = 21

Multiply both sides by 2

2 * \frac{1}{2}(4.5 + b_2) * 6 = 21 * 2

(4.5 + b_2) * 6 = 42

Divide through by 6

4.5 + b_2 = 42/6``

4.5 + b_2 = 7

b_2 =  7 - 4.5

b_2 =  -2.5

6 0
2 years ago
If 10a+10b=35, what is the average (arithmetic mean) of a and b?
worty [1.4K]

Answer:

1.75

Step-by-step explanation:

If a  and b are two numbers, then their arithmetic mean is

\dfrac{a+b}{2}

Given:

10a+10b=35

Divide this equation by 10:

a+b=3.5

Now, divide it by 2:

\dfrac{a+b}{2}=\dfrac{3.5}{2}\\ \\\dfrac{a+b}{2}=1.75

6 0
2 years ago
Ice cream usually comes in 1.5-quart boxes (48 fluid ounces), and ice cream scoops hold about 2 ounces. However, there is some v
Troyanec [42]

Answer:

(a) The expected value and standard deviation of the amount of ice cream served at the party are 54 ounces and 1.25 ounces respectively.

(b) The expected value and standard deviation of the amount of ice cream left in the box after scooping out one scoop are 46 ounces and 1.031 ounces respectively.

(c) Because the variance of each variable is dependent on the other.

Step-by-step explanation:

The random variable <em>X</em> and <em>Y</em> are defined as follows:

<em>X</em> = amount of ice cream in the box

<em>Y</em> = amount of ice cream scooped out

The information provided is:

E (X) = 48

SD (X) = 1

V (X) = 1

E (Y) = 2

SD (Y) = 0.25

V (Y) = 0.0625

(a)

The total amount of ice-cream served at the party can be expressed as:

<em>X</em> + 3<em>Y</em>.

Compute the expected value of (<em>X</em> + 3<em>Y</em>) as follows:

E(X+3Y)=E(X)+3E(Y)\\= 48+(3\times2)\\=48+6\\=54

Compute the variance of (<em>X</em> + 3<em>Y</em>) as follows:

V(X+3Y) = V (X)+3^{2}V(Y)+2\times 3Cov (X,Y)\\=1+(9\times0.0625)+0\\=1.5625

Then the standard deviation of (<em>X</em> + 3<em>Y</em>) is:

SD(X + 3Y) =\sqrt{V(X + 3Y)}\\\sqrt{1.5625}\\=1.25

Thus, the expected value and standard deviation of the amount of ice cream served at the party are 54 ounces and 1.25 ounces respectively.

(b)

The amount of ice-cream left in the box after scooping out one scoop is represented as follows:

<em>X</em> - <em>Y</em>.

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E(X-Y)=E(X)-E(Y)\\=48-2\\=46

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V(X - Y) =V(X)+V(Y)-2Cov(X,Y)\\=1+0.0625-0\\=1.0625

Then the standard deviation of (<em>X</em> - <em>Y</em>) is:

SD(X-Y) =\sqrt{V(X -Y)}\\\sqrt{1.0625}\\=1.031

Thus, the expected value and standard deviation of the amount of ice cream left in the box after scooping out one scoop are 46 ounces and 1.031 ounces respectively.

(c)

The variance of the sum or difference of two variables is computed by adding the individual variances. This is because the variance of each variable is dependent on the others.

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2 years ago
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2 years ago
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Viefleur [7K]

Answer:

c

Step-by-step explanation:

6 0
2 years ago
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