We can solve this equation by using the Square Root Method.
First, take the square root of each side of the equation:
(x-8)^2 = 144 becomes x-8 = 12
Then add 8 to both sides.
x=20
The original lawn was d. 20 feet by 20 feet.
<h3>
Hey!</h3>
<em><u>To solve the missing number of the original amount of gallons that were in the tank is simply by adding the two numbers we have: </u></em>
<em><u></u></em>
9+3= 12 gallons
<u><em>To make sure 12 was the original number, subtract 12 from 9. </em></u>
<u><em /></u>
<u><em>12-9= 3 gallons </em></u>
So your answer to your question is 12 gallons!
Hope this helped! °ω°
Answer:-4(2x - 1) > 5 - 3x
solution:
-4(2x) -4(-1) > 5 - 3x Distribute -4 to get -8x + 4 > 5 - 3x
-8x + 4 > 5 - 3x
+3x + 3x
-5x + 4 > 5
- 4 -4
-5x > 1
÷ -5 ÷ -5
x < - 1/5
<span>Let x = dollar increase in price
Let y = fewer number of pairs sold
Since 2 fewer shoes are sold for each 1 dollar (factor of 2)
y = 2x
Revenue = Number of shoes sold * Price charged per shoe
Number of shoes sold = 200 - y = 200 - 2x
Price charged per shoe = $60 + $x
Revenue = (200 - 2x)(60 + x) = -2x^2 + 200x - 120x + 12000
Revenue = -2x^2 + 80x + 12000
In a quadratic equation, Revenue is maximized when x = -b / 2a. In this case:
x - -80 / (2*-2) = $20
Price charged per show = $60 + $x = $60 + $20 = $80.
Maximum revenue = -2x^2 + 80x + 12000 (evaluated at x = $20)
Maximum revenue = -2(20^2) + 80*20 + 12000 = $12800</span>
Answer:
Area of drawing= 0.315 m²
Step-by-step explanation:
Base = 6m
Height = 4.2 m
Area = height* base
Area= 4.2*6
Area= 25.2 m²
The scale is 10 cm on the drawing for every 8 meters on the sculpture.
Which is 10 cm to 800 cm
Or
0.1m to 8m
Arra of sculpture= 25.2 m²
area of drawing= (25.2*0.1)/8
Area of drawing= 0.315 m²
