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2 years ago

Use the domain {-1, 0, 1, 2, 3, 4} and plot the points on the graph that would best satisfy the equation y = 2x.

1 answer:

4 0

Domain is ur x values

y = 2x...when x = -1
y = 2(-1)
y = -2.....(-1,2) satisfies this equation

y = 2x....when x = 0
y = 2(0)
y = 0....(0,0) satisfies it

y = 2x....when x = 1
y = 2(1)
y = 2....so (1,2) satisfies it

y = 2x....when x = 2
y = 2(2)
y = 4....(2,4) satisfies it

y = 2x...when x = 3
y = 2(3)
y = 6.....(3,6) satisfies it

y = 2x...when x = 4
y = 2(4)
y = 8.....(4,8) satisfies it

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2 years ago

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Adam is working two summer jobs, making $9 per hour washing cars and $8 per hour walking dogs. Last week Adam earned a total of

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Answer:

Washing cars= 4 hours

Walking dogs= 10 hours

Step-by-step explanation:

You want to start by creating equations. So one thing we know is that he makes $9 an hour washing cars(x) and $8 walking dogs(y).

$9x+$8y=$116

The second Equation is based off of the hours worked. We know that he worked 6 hours more walking the dogs than he did washing cars, so we can take x(being the washing hours) and add 6 to it to equal y (the number of dog hours).

y=x+6

Now You plug what y equals into the first equation to solve for x.

9x+8(x+6)=116 Next distribute the 8 to each term.

9x+8(x)+8(6)=116

9x+8x+48=116 Add the like terms together (9x+8x)

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-48 -48

17x=68 Now divide by 17 on both sides.

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17 17

x=4 Finally we can take x and plug it back in to one of the equations in order to solve for y. I'm going to choose the second equation.

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2 years ago

In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a

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Answer:

T = - 7.5 Cos π/12( t - 4 ) + 10.5

Step-by-step explanation:

Given that the

Maximum temp. = 18 degree Celsius

Minimum temp. = 3 degree Celsius

The half way between 10 am and 10 pm is 4 am

The sine and cosine functions can be used to model fluctuations in temperature data through out the year. An equation that can be used to model these data is of the form:

T = A cos B(t - C) + D, where A,B,C,D, are constants, T is the temperature in °C and t is the hour (1–24)

A = amplitude = (Tmax - Tmin)/2

A = (3 - 18)/2 = - 15/2 = -7.5 ( note : after midnight)

B = 2π/24 = π/12

C = units translated to the right

C = 4

D = ymin + amplitude = units translated up

D = 7.5 + 3 = 10.5

The formula of the trigonometric function that models the temperature T in Johannesburg t hours after midnight we be

T = - 7.5 Cos π/12( t - 4 ) + 10.5

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2 years ago

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2 years ago