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NISA [10]
2 years ago
8

A student estimated the sum 7.95 + 8.11 + 78.5 + 8.05 + 79.4 + 0.815 as: All the numbers begin with a 7 or 8, so use cluster est

imation. 8 + 8 + 80 + 8 + 80 + 0.8 = 184.8 Explain why this reasoning is not accurate.
Mathematics
2 answers:
Alenkinab [10]2 years ago
5 0

Answer with explanation:

We have to estimate the sum of

→7.95 + 8.11 + 78.5 + 8.05 + 79.4 + 0.815

When Rounded to nearest tens

7.95 → 8.00

8.11→ 8.00

78.5→79

8.05→8.00

79.4→79.0

0.815→1

So,estimation of the above rational numbers with addition as an operation is done,the result is

→8 + 8 + 80 + 8 + 80 + 0.8 = 184.8, is not correct ,because in the expression it is not clear , the numbers are neither exactly rounded to nearest tens or tenths.

for example ,79.4 when rounded to nearest tens → 79,but in the expression 80 is written,which is not correct.

Similarly,when rounded to nearest tens, 0.815 → 1, but in the expression 0.8 is written,which is confusing.

Similarly,when rounded to nearest tens ,78.5 →79 , but in the expression 80, is written,which is incorrect.

CaHeK987 [17]2 years ago
3 0

The numbers are not clustered around a common number. Two of the numbers are very large and one is very small.

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What is the length of AC ?<br><br> 3ft<br> 4ft<br> 9ft<br> 18ft
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ΔACB and ΔMNB are similar. Therefore the corresponding sides are in proportion:

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5 0
2 years ago
Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178
Katarina [22]

Answer:

2x+178\geq 2000

Step-by-step explanation:

Let, the number of cans collected by Shane = x.

So, the number of cans collected by Abha = x + 178.

Since, at least 2000 cans are required to be collected.

Thus, we have the inequality,

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i.e. x+(x+178)\geq 2000

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4 0
2 years ago
Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be t
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Answer:The pool must have been the same depth at the start of the interval as it was at the end of the interval.

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The average rate of change is calculated as:

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Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

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That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

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