To find the average assessment, add the 5 grades together, then divide by the quantity of grades added together (in this case 5).
=56 + 42 + 47 + 59 + 48
=252
=252 ÷ 5
=50.4 average
ANSWER: Yes, he passes his course with an average grade of 50.4.
Hope this helps! :)
No, the trailer cannot hold the weight of the bricks. It is beyond the 900kg capacity of the trailer. The total weight of the bricks is 1,013.77 kilograms. The total weight was derived from getting the volume of the brick (0.051m x 0.102m x 0.203m), then multiplying the volume to the density of each brick (1.056 x 10^3m^3 x 1920kg/m^3). The weight of each brick is 2.03kg. Lastly, multiply the total number of bricks to the weight of each brick to get the total weight.
Answer:
<h2>√512 by √512 </h2>
Step-by-step explanation:
Length the length and breadth of the rectangle be x and y.
Area of the rectangle A = Length * breadth
Perimeter P = 2(Length + Breadth)
A = xy and P = 2(x+y)
If the area of the rectangle is 512m², then 512 = xy
x = 512/y
Substituting x = 512/y into the formula for calculating the perimeter;
P = 2(512/y + y)
P = 1024/y + 2y
To get the value of y, we will set dP/dy to zero and solve.
dP/dy = -1024y⁻² + 2
-1024y⁻² + 2 = 0
-1024y⁻² = -2
512y⁻² = 1
y⁻² = 1/512
1/y² = 1/512
y² = 512
y = √512 m
On testing for minimum, we must know that the perimeter is at the minimum when y = √512
From xy = 512
x(√512) = 512
x = 512/√512
On rationalizing, x = 512/√512 * √512 /√512
x = 512√512 /512
x = √512 m
Hence, the dimensions of a rectangle is √512 m by √512 m
