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Nana76 [90]
1 year ago
5

Find the binomial coefficient: 2012/2011

Mathematics
1 answer:
seropon [69]1 year ago
4 0
 ²⁰¹²C₂₀₁₁ = (2012)! / [(2011)! (2012-2011)!]

²⁰¹²C₂₀₁₁ = (2012)! / [(2011)! (1)!]

Simplify 2012! / (2011)! = 2012

²⁰¹²C₂₀₁₁ = (2012)! / (1)!  = 2012
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Darius and Barb are playing a video game in which the higher score wins the game. Their scores are shown below. Darius’s scores:
Bumek [7]

Answer:

Darius is correct if only the median score is considered.

Step-by-step explanation:

Darius scores are; 96, 54,120, 87, 123

arrange the scores in increasing order;

54,87,96,120,123

mean = (54+87+96+120+123)/5 =480/5 =96

median =96

Barb's scores are  92,94,96,98,110

mean=(92,94,96,98,110)/5 =490/5=98

median score=96

⇒if the median score only is considered; then it is a tie because the score is 96 in both players.

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2 years ago
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Dalia flies an ultralight plane with a tailwind to a nearby town in 1/3 of an hour. On the return trip, she travels the same dis
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Dalia had an average airspeed of ⇒ 42 miles per hour.
The average wind speed was  ⇒ 12 miles per hour.

8 0
2 years ago
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Alison is saving for retirement. Her company matches what she puts into her 401K in a ratio of 2:3. If she puts in $400 each mon
inessss [21]
Id say B...............
6 0
1 year ago
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Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1
irina [24]
\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)
\end{cases}\\\\
-------------------------------\\\\
\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\
-------------------------------\\\\
c=\textit{distance from the center to either foci}\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)

5 0
1 year ago
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If the parent function is f(x) = x3, which transformed function is shown in the graph? g(x) = (x − 3)3 , g(x) = (x + 3)3 , g(x)
sveticcg [70]
A. cause  i did it on the calculator so i know its right
3 0
2 years ago
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