Question

a commercial jet airplane climbs at takeoff with slope m=4/9. How far in the horizontal direction will the airplane fly to reach am altitude of 20,000 ft above the takeoff point?

Answer 1

$\bf slope = {{ m}}= \cfrac{rise}{run}\implies \cfrac{\textit{vertical direction}}{\textit{horizontal direction}}\implies \cfrac{4}{9}=\cfrac{20000}{h}$

solve for "h".