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In-s [12.5K]
2 years ago
7

1) Determine which events are mutually exclusive and which are not, when a single card is drawn from a deck. a. Getting a 7 and

getting a jack b. Getting a club and getting a king c. Getting a face card and getting an ace d. Getting a face card and getting a spade
Mathematics
1 answer:
Allisa [31]2 years ago
7 0

Answer:

The events a) and c) are mutually exclusive.

Step-by-step explanation:

a) This is mutually exclusive, each card has a unique value between 2 and 10, or it is a jack, queen, king, or an Ace. A single card cant have two different values at the same time.

b) This is not mutually exclusive, since you can get a king of clubs. Each card can have any combination of one suit and one value.

c) A face card is either a Jack, a Queen or a King, it is not an Ace. For the same argument of a), a card cant have two different values, therefore this event is mutually exclusive.

d) This is not mutually exclusive, since a card can have any suit independently of the value it has (same argument than b), therefore, a card can be a face card and a spade at the exact time.

Therefore, events a and c are mutually exclusive.

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Peter is at a lumber yard. He gets 2 free boxes of nails for every 10 boards he buys. Write an expression for the number of boxe
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A. The number of 10-boards Peter bought is equal to n divided by 10. Then, each of the 10-boxes will get two boxes of nails. The number of boxes of nails that Peter will have after buying n boards will be,

    N = (2)(n/10)

Simplifying,

<em>   N = n/5</em>

b. If the number of boards are 90 then,

     N2 = (90/10)(2)(100 nails/box)
     N2 = 1800

Answer: 1800
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2 years ago
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Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can
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Answer:

The answer is 3√5 mi.

The formula is: d = √(3h/2)

Wyatt:

h = 120 ft

d = √(3 * 120/2) = √180 = √(36 * 5) = √36 * √5 = 6√5 mi

Shawn:

h = 270 ft

d = √(3 * 270/2) = √405 = √(81 * 5) = √81 * √5 = 9√5 mi

How much farther can Shawn see to the horizon?

Shawn - Wyatt = 9√5 - 6√5 = 3√5 mi

3 0
2 years ago
Flip two coins 100 times, and record the results of each coin toss in a table like the one below:
monitta

Answer:

1)The theoretical probability that a coin toss results in two heads showing is 25%.

2)The experimental probability that a coin toss results in two heads showing is 44%.

3) The theoretical probability that a coin toss results in two tails showing is 25%.

4) The experimental probability that a coin toss results in two tails showing is 34%.

5) The theoretical probability that a coin toss results in one head and one tail showing is 50%.

6) The experimental probability that a coin toss results in a head and a tail is 22%.

7) The experimental probabilities are slightly different from the theoretical probabilities because the number of experiments is relatively small. As the number of experiments increase, the experimental probabilities will get closer to the theoretical probabilities.

Step-by-step explanation:

Probability:

What you want to happen is the desired outcome.

Everything that can happen iis the total outcomes.

The probability is the division of the number of possible outcomes by the number of total outcomes.

Theoretical Probability:

The results you expect to happen.

Experimental Probability:

The probability determined from the result of an experiment.

1. What is the theoretical probability that a coin toss results in two heads showing?

In each toss, the theoretical  probability that a coin toss results in a head showing is 50%.

So for two coins, the probability is:

P = (0.5)^{2} = 0.25

The theoretical probability that a coin toss results in two heads showing is 25%.

2. What is the experimental probability that a coin toss results in two heads showing?

There were 100 flips, and it resulted in two heads 44 times, so:

P = \frac{44}{100} = 0.44

The experimental probability that a coin toss results in two heads showing is 44%.

3. What is the theoretical probability that a coin toss results in two tails showing?

In each toss, the theoretical  probability that a coin toss results in a tail showing is 50%.

So for two tails, the probability is:

P = (0.5)^{2} = 0.25

The theoretical probability that a coin toss results in two tails showing is 25%.

4. What is the experimental probability that a coin toss results in two tails showing?

There were 100 flips, and it resulted in two tails 34 times, so:

P = \frac{34}{100} = 0.34

The experimental probability that a coin toss results in two tails showing is 34%.

5. What is the theoretical probability that a coin toss results in one head and one tail showing?

In each toss, the theoretical probability that a coin toss results in a tail showing is 50% and in a head showing is 50%.

They can be permutated, as the tail can appear before the head, or the head before the tail. So:

P = p_{2,1}*(0.5)*(0.5) = \frac{2!}{1!}*0.25 = 0.50

The theoretical probability that a coin toss results in one head and one tail showing is 50%.

6. What is the experimental probability that a coin toss results in one head and one tail showing?

There were 100 flips, and it resulted in a head and a tail showing 22 times, so:

P = \frac{22}{100} = 0.22

The experimental probability that a coin toss results in a head and a tail is 22%.

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Answer- it’s A

Step-by-step explanation:

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Total vegetable = 8 × 36 = 288 vegetables

We can have 8 different vegetables, each type can have 36 vegetables
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