Ask question

Ask question

All categories

2 years ago

10

Gene paid a deposit on a leased car. The deposit earns 2.8 percent simple annual interest. At the end of the year, the interest

that is earned is $22.40. What was the amount of the original deposit?

2 answers:

RSB [31]2 years ago

7 0

The formula is
I=prt
I interest earned 22.4
P original deposit ?
R interest rate 0.028
T time 1 year
Solve the formula for p to get
P=I÷rt
P=22.4÷(0.028×1)
P=800

Amiraneli [1.4K]2 years ago

3 0

Interest = principle * rate * time...
I = PRT...we are going to rearrange this because we are looking for the principle...

I / (RT) = P
I = 22.40
R = 2.8%...turn to a decimal = 0.028
T = 1

sub and solve
22.40 / (0.028(1) = P
22.40 / 0.028 = P
800 = P....amount of original deposit is $ 800 <==

You might be interested in

Mark has a 25 ounce drink. He drinks 5 ounces. What percent of the drink does he have left?

valina [46]

Answer: $80\%$

Step-by-step explanation:

This problem can be solved by the <u>Rule of Three</u>, which is a mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known.

In this case, the 25 ounce drink represents the $100 \%$ . So, if Mark drinks 5 ounces, this means he has 20 ounces left and we have to find the percent this represents:

$25 oz$ ------- $100\%$

$20 oz$ -------- $?$

$?=\frac{(20 oz)(100\%)}{25 oz}$

$?=80\%$ This is the percent of the drink Mark has left

4 0

2 years ago

Mr. Cruz fills a 3-gallon water cooler for a family picnic. He brings plastic cups that each hold 12 fluid ounces of water. How

oksian1 [2.3K]

One gallon is equivalent to 128 fluid ounces

3 gallons is equivalent to 3*128 fluid ounces

= 384 fluid ounces

One plastic cup can hold 12 guide ounces

So cups needed will be 384/12

32 cups

8 0

1 year ago

Use the scale and map measurements to find the actual distance from New Wilmington to Sharon through Mercer. What is the actual

Fynjy0 [20]

Your answer is C!

Hope i helped!

~Cakes

8 0

2 years ago

Read 2 more answers

Prove this (sinx-tanx)(cosx-cotx)=(sinx-1)(cosx-1)

Ilya [14]

<span><span>(<span>sinx</span>−<span>tanx</span>)</span><span>(<span>cosx</span>−<span>cotx</span>)</span></span>

<span>=<span>(<span>sinx</span>−<span><span>sinx</span><span>cosx</span></span>)</span><span>(<span>cosx</span>−<span><span>cosx</span><span>sinx</span></span>)</span></span>

<span>=<span>sinx</span><span>(1−<span>1<span>cosx</span></span>)</span><span>cosx</span><span>(1−<span>1<span>sinx</span></span>)</span></span>

<span>=<span>sinx</span><span>(<span><span>cosx</span><span>cosx</span></span>−<span>1<span>cosx</span></span>)</span><span>cosx</span><span>(<span><span>sinx</span><span>sinx</span></span>−<span>1<span>sinx</span></span>)</span></span>

<span>=<span><span>sinx</span><span>cosx</span></span><span>(<span>cosx</span>−1)</span><span><span>cosx</span><span>sinx</span></span><span>(<span>sinx</span>−1)</span></span>

<span>=<span>(<span>cosx</span>−1)</span><span>(<span>sinx</span>−1<span>)</span></span></span>

6 0

2 years ago

Read 2 more answers

Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi

miss Akunina [59]

Answer:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

Step-by-step explanation:

1st boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a$

Equation:

$y=ax^2 -2ax+c$

The y-coordinate of the vertex:

$y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1$

Solve:

$c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}$

Parabola equation:

$y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}$

2nd boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0$

Equation:

$y=ax^2+c$

The y-coordinate of the vertex:

$y_v=a\cdot 0^2+c\Rightarrow c=-7$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-7\\ \\64a-7=1$

Solve:

$a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7$

Parabola equation:

$y=\dfrac{1}{8}x^2 -7$

System of two equations:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

7 0

2 years ago

Read 2 more answers