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Anna11 [10]
2 years ago
3

Kurt wants to have $25,000 in an investment account four years from now. the account will pay 0.2 percent interest per month. if

he saves money every month, starting one month from now, how much will he have to save each month to reach his goal
Mathematics
2 answers:
JulijaS [17]2 years ago
7 0

Answer:

Step-by-step explanation:

Natali5045456 [20]2 years ago
5 0
Given:
F = 25000, future value
i=0.02 per month, compounded monthly
n=4*12=48 periods (months)
Need A=monthly deposit

The amount A is given by the formula
A=Fi/((1+i)^n-1)  [can be derived from the annuity formula]
=25000*0.02/((1.02^48-1)
= 315.05

Answer: Kurt will need to save $315.05 each month to reach the goal of saving $25000 after 4 years.
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Complete the following multiplication exercises.
olga2289 [7]
43x7=301
12x9=108
10x6=60
9x7=63
7x5=35
6x3=18
0x8=8
30x3=90
11x8=88
73x2=219
83x5=415
16x8=128
392x7=2,744
29x4=116
761x9=6,849
4,829x6=28,974
12x7=84
25,500x4=102,000
4 0
2 years ago
Read 2 more answers
A box of buttons contains the same number of each type of button. It contains 220g of buttons
ra1l [238]

Answer:

a) 18 button a buttons are required to fill the bag.

b) 12 button b buttons are required to fill the bag.

c) There are 11 buttons of each type in the box containing 220 g of buttons.

Step-by-step explanation:

Complete Question

Two button types, button a weighing 8 grams and button b weighing 12 grams. The buttons are sold in bags. Each bag contains 144 grams of buttons.

a) How many of button a are needed to fill one bag?

b) How many of button b are needed to fill one bag?

c) A box of buttons contains the same number of each type of button it contains 220g of buttons. How many of each type of button are in the box.

Solution

a) A bag contains 144 grams of buttons.

Button a weighs 8 grams per button.

Total number of button a buttons required to fill up the bag = (144/8) = 18 button a buttons.

b) A bag contains 144 grams of buttons.

Button b weighs 12 grams per button.

Total number of button b buttons required to fill up the bag = (144/12) = 12 button a buttons.

c) A box of buttons weighing 220 g contains the same number of each type of button.

Let this number be n.

This means the Total weight of button a buttons in this box = 8n

total weight of button b buttons in this box = 12n

Sum total of the weight of the buttons = 8n + 12n = 20n

20n = 220

n = (220/20) = 11.

This means there are 11 buttons of each type in the box containing 220 g of buttons.

Hope this Helps!!!

6 0
2 years ago
Janet makes 67% of free throws in her basketball games. Her coach wants to know the probability that she will make 7 out of the
8_murik_8 [283]
The probability that Janet makes a free throw is given by:
P(f)=0.67
The simulation that will be used to design the possibility of her making 7 out of 8 free throws will be:

<span>D) Roll a die letting 1-4 represent Janet making a free throw and 5-6 represent Janet not falling. Roll the die eight times.
This is is because the probability of obtaining 1,2,3 or 4 from rolling a dice is
4/6=0.67 </span>
3 0
2 years ago
Read 2 more answers
Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De
Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is,\lambda=\frac{1}{\mu}=\frac{1}{7}.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx

                      =\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0
2 years ago
Find the measure of each acute angle.
crimeas [40]

The 3 inside angles of a triangle need to equal 180 degrees.

This is a right triangle so the bottom left corner is 90 degrees.

This means the other two angles when added need to equal 180-90 = 90 degrees.

Now you have 8x + 7x = 90

Combine like terms:

15x = 90

Divide both sides by 15

X = 6

Now you have the value for x solve the two angles:

8x = 8(6) = 48

7x = 7(6) = 42

Top left = 48 degrees

Bottom right = 42 degrees

8 0
2 years ago
Read 2 more answers
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