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Studentka2010 [4]
1 year ago
9

You need to stabilize a flagpole by string in a guy-wire from the top of a flagpole to the ground. The pole is 15 feet tall and

angle of elevation is 70 degrees. Using trig ratios calculate how much wire is needed

Mathematics
2 answers:
Mandarinka [93]1 year ago
7 0
Sinα=h/w

w=h/sinα, we are told that h=15 ft and α=70° so

w=15/sin70° ft

w≈15.96 ft (to nearest hundredth of a foot)
Leto [7]1 year ago
6 0
<h2>Answer:</h2>

The length of the wire needed is:

                15.9625 feet

<h2>Step-by-step explanation:</h2>

We will model this problem with the help of a right angled triangle such that the side opposite to the angle 70 degree is: 15 feet.

Now, we are asked to find the amount of wire used i.e. we are asked to find the hypotenuse of the right angled triangle.

We will use the sine trignometric ratio as follows:

\sin 70=\dfrac{15}{x}\\\\i.e.\\\\x=\dfrac{15}{\sin 70}\\\\i.e.\\\\x=\dfrac{15}{0.9397}\\\\i.e.\\\\x=15.9625\ feet

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Answer:

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6 0
2 years ago
A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the im
loris [4]

Answer:

Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).

As, DO is Dilation of Δ ABC by Scale factor of \frac{1}{2}.

Vertices of A' B'C' are

A'=(\frac{-4}{2},\frac{3}{2})=(-2,\frac{3}{2}), B'=(\frac{4}{2},\frac{4}{2})=(2,2), C'=(\frac{1}{2},\frac{1}{2})

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.

The two triangles will be congruent.

AO is Dilated by a factor of half , so A'O' will be half of AO.

So, correct Statements are

1. AB is parallel to A'B'.

2.DO,1/2(x, y) =  

The distance from A' to the origin is half the distance from A to the origin.

OA=\sqrt{(-4)^2+3^2}=\sqrt{25}=5\\\\ O'A'=\sqrt{2^2+(\frac{3}{2})^2}=\frac{5}{2}=2.5

8 0
2 years ago
Read 2 more answers
33s^5t^4u^8 ÷ 11st^3u^8
miskamm [114]

Answer:

3s^{4}t\\

Step-by-step explanation:

7 0
1 year ago
A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical
Korolek [52]

Answer:

78% probability that a randomly selected online customer does not live within 50 miles of a physical​ store.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Total outcomes:

100 customers

Desired outcomes:

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.

Using this​ estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical​ store?

p = \frac{78}{100} = 0.78

78% probability that a randomly selected online customer does not live within 50 miles of a physical​ store.

4 0
2 years ago
If r is the midpoint of qs rs=2x-4, st= 4x-1 and rt = 8x-43 find qs
sammy [17]

Answer:

QS=68\ units

Step-by-step explanation:

step 1

Find the value of x

we know that

r is the midpoint of qs

so

QR=RS

QS=QR+RS------> QS=2RS -----> equation A

RT=RS+ST ----> equation B

see the attached figure to better understand the problem

Substitute the given values in the equation B and solve for x

8x-43=(2x-4)+(4x-1)

8x-43=6x-5

8x-6x=43-5

2x=38

x=19

step 2

Find the value of RS

RS=2x-4

substitute the value of x

RS=2(19)-4

RS=34\ units

step 3

Find the value of QS

Remember equation A

QS=2RS

so

QS=2(34)=68\ units

6 0
2 years ago
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