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2 years ago

suppose an investment of $8200 doubles in value every 7 years. how much is the investment worth after 28 years

Mathematics

2 answers:

Yuliya22 [10]2 years ago

5 0

Answer:

After 28 years, it will be $131,200

Step-by-step explanation:

It is given that the investment doubles in value every 7 years.

So, after 7 years, it will be 8200 × 2 = 16,400

After 14 years, it will be 16,400 × 2 = 32,800

After 21 years, it will be 32,800 × 2 = 65,600

After 28 years, it will be 65,600 × 2 = 131,200

Hence, the investment is $131,200 worth after 28 years.

kicyunya [14]2 years ago

3 0

Suppose an investment of $8200 doubles in value every 7 years. how much is the investment worth after 28 years

131,200

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John needs 13 bottles of water from the store. john can only carry 3 at a time. what's the minimum number of trips john needs to

Lostsunrise [7]

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2 years ago

For the sequence an = 2n + 1, identify the values of a0 = _____, a1 = _____, a2 = _____, and a3 = _____.

Tresset [83]

Answer:

Option A - $a_0= 2,a_1= 3,a_2= 5,a_3= 9$

Step-by-step explanation:

Given : For the sequence $a_n= 2^n + 1$

To find : Identify the values of following?

Solution :

The nth term of the sequence is $a_n= 2^n + 1$

Substitute n=0,1,2 and 3

When n=0,

$a_0= 2^0+ 1$

$a_0= 1+1$

$a_0=2$

When n=1,

$a_1= 2^1+ 1$

$a_1= 2+1$

$a_1=3$

When n=2,

$a_2= 2^2+ 1$

$a_2=4+1$

$a_2=5$

When n=3,

$a_3= 2^3+ 1$

$a_3= 8+ 1$

$a_3= 9$

Therefore, The value is $a_0= 2,a_1= 3,a_2= 5,a_3= 9$

So, Option A is correct.

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2 years ago

The square of a number decreased by 3 times the number 28 find all possible values for the number

stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

$a^2 - 3a = 28$

$a^2 - 3a - 28 = 0$

Let us solve the above quadratic equation

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text { For } a^{2}-3 a-28=0 \text { we have } a=1, b=-3, c=-28$

$\begin{aligned}&a=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(1)(-28)}}{2 \times 1}\\\\&a=\frac{3 \pm \sqrt{9+112}}{2}\\\\&a=\frac{3 \pm \sqrt{121}}{2}=\frac{3 \pm 11}{2}\\\\&a=\frac{3+11}{2} \text { or } a=\frac{3-11}{2}\\\\&a=7 \text { or } a=-4\end{aligned}$