They would have to use micro dissection instruments
Answer:
Sister chromatids.
Explanation:
Sister chromatids are the two identical halves of a chromosome that are held together at centromere with help of cohesin. DNA replication in the S phase of the cell cycle doubles the amount of DNA. The copies of the DNA formed during DNA replication are accommodated in sister chromatids. Hence, two sister chromatids of a chromosome carry the identical DNA helices and associated proteins.
Answer:
several transcription factors (TFs)
Answer:
The all possible gametic haplotypes that can be made are described below.
Explanation:
According to the question, F1 progeny was produced by crossing a homozygous dominant parent with a homozygous recessive parent. As per the question, cross is to be made with a heterozygous parent, which will have solid unpatterned allele and blue colour with a homozygous recessive i.e lined, aqua lizard.
The possible haploid gametes for the heterozygous parent would be BL, bl, Bl, bL and for homozygous parent would be all bl.
Lactase refers to an enzyme that can dissociate lactose sugar into glucose and galactose. This enzyme plays an important role in the digestion of milk that comprises high lactose sugar. In case, if a mutation occurs in the gene codon of lactase, then two possibilities can take place. These are as follows:
1. Loss of mutation: In this case, the person becomes lactose intolerant because of mutation in lactase gene codon. Due to this, there is low mRNA expression and thus low production of the enzyme lactase. This is also known as lactase non-persistent phenotype.
2. Gain in mutation: In this case, the person gain an increase in mRNA expression of the lactase gene, thus more production of lactase takes place than usual. This kind of individual exhibits lactase persistent phenotype.
