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snow_lady [41]
2 years ago
12

A local PTA runs a fundraiser, selling lottery tickets for $5, offering 1 first prize of $100 and 5 second prizes worth $20 each

. They sell 100 tickets. What is the expected value of each ticket? -$3 $3 -$2.7 $2.7
Mathematics
1 answer:
Viktor [21]2 years ago
8 0
The expected value is the expected income less the expected cost.

The expected cost is a certain; it is $5.

The expected income is the probability of each possibility times its reward.

=> First prize: probability * prize = (1 / 100) * $ 100 = $1

=> Second prize: probability * prize = (5 / 100) * $20 = $1

Expected value = $1 + $1 - $5

Expected value = - $3

Answer: - $ 3
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What is the 185th digit in the following pattern 12345678910111213141516...?
Natalka [10]
1-9  = 9 digits
10-99 = 180 digits
So if we continue the pattern to 99, there are 189 digits, and the last 5 digits would be 79899.  Counting backwards: 189th = 9, 188th = 9, 187th = 8, 186th = 9, 185th = 7.

The 185th digit is 7.

4 0
2 years ago
A high percentage of people who fracture or dislocate a bone see a doctor for that condition. Suppose the percentage is 99%. Con
marishachu [46]

Answer:

(i) 0.15708

(ii) 0.432488

(iii) 3

Step-by-step explanation:

Given that, 99% of people who fracture or dislocate a bone see a doctor for that condition.

There is only two chance either the person having fracture or dislocation of bone will either see the doctor or not.

As per previous data, if one person got a fracture or dislocation of bone, the chance of seeing the doctor is 0.99. Assuming this chance is the same for every individual, so the total number of people having fractured or dislocated a bone can be considered as Bernoulli's population.

Let p be the probability of success represented by the chances of not seeing a doctor by any one individual having fractured or dislocated a bone.

So, p=1-0.99=0.01

According to Bernoulli's theorem, the probability of exactly r success among the total of n randomly selected from Bernoulli's population is

P(r)=\binom{n}{r}p^r(1-p)^{n-r}\cdots(i)

(i) The total number of persons randomly selected, n=400.

The probability that exactly 5 of them did not see a doctor

So, r=5 , p=0.01

Using equation (i),

P(r=5)=\binom{400}{5}(0.01)^5(1-0.01)^{400-5}

=\frac{400!}{(400-5)!\times 5!}(0.01)^5(0.99)^{395}

=0.15708

(ii) The probability that fewer than four of them did not see a doctor

=P(r

=P(r=0)+P(r=1)+P(r=2)+P(r=3)

=\binom{400}{0}(0.01)^0(0.99)^{400}+\binom{400}{1}(0.01)^1(0.99)^{399}+\binom{400}{2}(0.01)^2(0.99)^{398}+\binom{400}{3}(0.01)^3(0.99)^{397}

=0.017951+0.072527+0.146154+0.195856

=0.432488

(iii) The expected number of people who would not see a doctor

=np

=300\times 0.01

=3

7 0
2 years ago
Carol ate 2/5 of the cake, Dima ate 3/8 of the REMAINING cake, mom ate the rest.
Anarel [89]
She would've eaten half of the cake, or 8 oz.
4 0
2 years ago
A horticulturist conducted an experiment on 110 thirty-six inch plant boxes to see if the amount of plant food given to the plan
djyliett [7]

Skejsbssbdgdhdhjslslakasksnshshsksisikssjsjsjjsjsjsjsjss

8 0
2 years ago
Max's cell phone plan charges a monthly
ludmilkaskok [199]

Answer:

21

Step-by-step explanation:

7.41 / 0.13 = 57

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42 / 2 = 21

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6 0
2 years ago
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