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mamaluj [8]
2 years ago
6

What is the approximate width of a 90 percent confidence interval for the true population proportion if there are 12 successes i

n a sample of 25?
Mathematics
1 answer:
creativ13 [48]2 years ago
6 0

To find for the value of the approximate width or margin of error, we make use of the following formula:

approximate width = ± z [p (1 – p) / n]^0.5

 

where,

z = z score can be obtained using normal distribution tables at 90% confidence level

p = probability of success

n = number of samples = 25

 

Using the standard distribution tables, the value of z at 90% level is:

z = 1.645

 

The probability of success is 12 out of 25, therefore:

p = 12 / 25 = 0.48

 

Therefore the approximate width is:

approximate width = ± 1.645 [0.48 (1 – 0.48) / 25]^0.5

approximate width = ± 1.645 (0.0999)

approximate width = ± 0.164

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Answer:

Option D is correct.

An equation: h = 28000 -2000m

Step-by-step explanation:

Let h represents the height of the airplane and m represents the minutes.

As per the given statement: An airplane 28,000 feet above ground begins descending at a constant rate of 2,000 feet per minute.

At ground m = 0

h(0) = 28000 feet.

⇒ An airplane descending at a constant rate (r) = - 2000 feet per minute

then,

height(h) of the airplane after m minutes is given by:

h(m) = 28000 - rm ; where r is the rate descending at constant rate and m is the minutes.

Substitute the given values we get;

h(m)= 28000 -2000m

Therefore, an equation which gives the height, h of the airplane after m minutes is; h = 28000 -2000m


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