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IceJOKER [234]
2 years ago
4

Maritza remembers her PIN because it is the product of two consecutive prime numbers that is between 1000 and 1500. What is her

PIN?
Mathematics
1 answer:
sesenic [268]2 years ago
8 0

Martiza’s pin number is between 1000 and 1500

It is the product of two consecutive prime numbers

Prime numbers are the numbers that can only be divided by one or itself.

So, prime numbers are 1, 3, 5, 7,………29, 31,37, 41, …..

If we multiply 29 and 31, 29 x 31 = 899 which is not between 1000 and 1500

Next, 31 x 37 = 1147 this is between 1000 and 1500

Next 37 x 41 = 1517, which is above 1500

<span>So, 1147 is her pin number.</span>

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Use the formula of the present value of annuity ordinary.
The formula is
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Diano4ka-milaya [45]

The expression for number of hours is: C. (3.39 × 10^7) ÷ (3.6 × 10^4)

The equations with no solutions are : A,B and C.

Step-by-step explanation:

The formula for time is distance divided by speed.

The distance given is 3.39 × 10⁷ miles.

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B.

Test to see if the equations have solutions;

(3x+4y=5)--------multiply by 6

(6x+8y=10 )-------multiply by 3

18x+24y=30

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The same to option B,and C.

For option D;

3x+6y=1

x+y=0 -------this can be written as x= -y

Sustitute x=-y in the first equation

3(-y) +6y =1

-3y+6y=1

3y=1

y=1/3

But x+y=0

Hence;

x+1/3=0

x=-1/3

solution ( -1/3, 1/3)

Lean More

Formula for speed:brainly.com/question/8311838

Solving inequalities:brainly.com/question/11213549

Keywords: distance, average speed, time, equations, solutions

#LearnwithBrainly

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Nonamiya [84]

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

<h2>Explanation:</h2>

As I understand, in this exercise, we have the following numbers:

\text{Number 1}=\sqrt{79} \\ \\ \text{Number 2}=\sqrt{63} \\ \\ \text{Number 3}=\sqrt{143} \\ \\ \text{Number 4}=4\pi

By using calculator, let's convert those numbers into decimal form:

\text{Number 1} \approx 8.88\\ \\ \text{Number 2} \approx 7.93 \\ \\ \text{Number 3} \approx 11.96 \\ \\ \text{Number 4} \approx 12.56

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\text{Number 2} \\ \\ \text{Number 1} \\ \\ \text{Number 3} \\ \\ \text{Number 2}

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\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

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Answer:

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