It would be: k+3 = 10
subtracting 3 from both sides,
k+3-3 = 10-3
k=7
Let event A be the first light being red.
Let event B be the second light being red.
P(A) = 0.48
P(A & B) = P(A) * P(B) = 0.35
P(B) = 0.35 / P(A)
P(B) = 0.35 / 0.48
P(B) = 0.73
Since the lights are independent, P(B|A) = P(B) therefore d is the correct answer.
Answer:
C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.
Step-by-step explanation:
The center for Simulation A and Simulation B will be roughly equal.
Overall Sample size of Simulation A = 1500 * 100 = 150000
Overall Sample size of Simulation B = 2000 * 50 = 100000
Since the sample size for Simulation A is greater, the variability of Simulation will be less.
Therefore, The answer is C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.
