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2 years ago

How much times does 7 go into 48??

Mathematics

2 answers:

VLD [36.1K]2 years ago

8 0

7 can go into 48 6 times because 7 times 6 = 42 and 7*7=49 so 6 times

Sedbober [7]2 years ago

5 0

7 goes into 48, 6 times.
7 * 6 = 42.
If you did 7 * 7 it equals 49 which goes over 48, so it would not work. Therefor your answer is 6.

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Jake's morning run was a distance of 9.3 miles. He ran back and forth on one long straight street. He started at his house and r

Sergeeva-Olga [200]

Answer: the distances can be 0.65 miles (in the opposite direction to the school) or 4.65 miles (in the same direction as the school)

Step-by-step explanation:

Ok, the data that we have is:

Total distance = 9.3 mi.

The travel is:

House to school = 4 mi.

school to library = A

library to house = B

Now, we have that:

4mi + A + B = 9.3mi.

We have three possibilities:

1) The order of locations is: house, library, school

The travel from: school to library + library to house is equivalent to a travel between the school to the house = 4mi.

Then we have A + B = 4mi

4mi + A + B = 8mi ≠ 9.3mi

Then the library can not be between the house and the school.

2) The order of locations is: house, school, library.

In this case we have that the distance between the library and the house is equal to the distance between the house and the school plus the distance between the school and the library, then:

4mi + A = B.

We can replace this in our original equation:

4mi + A + B = 9.3mi

4mi + A + (4mi + A) = 9.3mi

8mi + 2*A = 9.3mi

2*A = 9.3mi - 8mi = 1.3mi

A = 1.3mi/2 = 0.65mi

Then the distance between the house and the library is:

The 4 miles between the house and the school, plus the 0.65 miles between the school and the library:

Distance = 4mi + 0.65mi. = 4,65mi

3) The third case is when the order of the locations is:

Library, house, school.

Then the distance between the house and the library is equal to the distance between the school and the library minus the distance between the house and the school, this is:

A - 4mi = B

Now we can replace this in our distance equation:

4mi + A + B = 9.3mi

4mi + A + (A - 4mi) = 9.3 mi

2A = 9.3mi

A = 9.3mi/2 = 4.65mi

Then the distance between the house and the library is:

B = A - 4mi = 4.65mi - A = 0.65mi

Then the distance between the house and the library is 0.65 miles in this case.

7 0

2 years ago

Kamila has a rectangular lawn that measures 80 by 150 feet. She wants to lay gravel made from colored rock in a border, 6 feet w

alex41 [277]

Answer:

1)Diagram attached

2)8424

3)1404

4)1569

Step-by-step explanation:

Diagram is attached

How many square feet of the gravel will surround the lawn:

Converting yards into feet:

1 yard =3 feet

So 80 yard =80(3) feet

=240 feet

and 150 yard =150 (3) feet

=450 feet

Area of rectangle is given by :length X width

Area of the outer border = (6+ 240+ 6 ) (6+ 450+6)

= 252 X 462

= 116424

Area of the lawn = 240 X 450

= 108000

Area of gravel border = 116424 - 108000

= 8424

Area of gravel border is 8424 ft^2

Total volume when depth is 2 inches:

converting inches to feet:

1 inch= 0.083 feet

2 inches =0.1667 feet

volume = base area X depth

=8424 X 0.1667

= 1404

total volume of gravel needed for the border is 1404 ft^3

Given:

A large bag of colored rock contains 5/8 of a cubic yard and costs $30

total cost of the rocks needed for the border=?

1 cubic yard = $30

converting cubic yard to cubic feet

1 cubic yard=27 cubic feet

cost of 1 cubic yard= cost of 27 cubic feet = $ 30

cost of 1 cubic feet=30/27

cost of 1404 cubic feet= 1404 X 30 / 27

= 1560

the total cost of the rocks needed for the border is $1560!

8 0

2 years ago

Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.

vodka [1.7K]

Answer:

<h3>- 128 Superscript StartFraction 3 Over x EndFraction </h3><h3>- (4RootIndex 3 StartRoot 2 EndRoot)x </h3><h3>- (4 (2 Superscript one-third Baseline) ) Superscript x</h3><h3>Step-by-step explanation:</h3>

Given the indicinal equation $(\sqrt[3]{128} )^{x}\\$

According to one of the law of indices,

$(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}$

Applying this law to the question;

$(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )$

The following are therefore true based on the following calculation

128 Superscript StartFraction 3 Over x EndFraction

(4RootIndex 3 StartRoot 2 EndRoot)x

(4 (2 Superscript one-third Baseline) ) Superscript x

5 0

2 years ago

Read 2 more answers

Which statements are true regarding the transformation? Check all that apply. EF corresponds to E'F'. FG corresponds to G'D'. ∠E

8090 [49]

Answer: A,C,D,F

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The speed of sound is approximately 340 m / s. How long will it take for the sound to travel from the batter to a spectator who

iris [78.8K]

The first answer is 3/34 sec and the second answer is 15/34 sec.

Set up a proportion for these problems. For the first question,
340/1 = 30/x

Cross multiply:
340*x = 1*30
340x = 30

Divide both sides by 340:
340x/340=30/340
x = 30/340 = 3/34

For the second question,
340/1 = 150/x

Cross multiply:
340*x = 150*1
340x=150

Divide both sides by 340:
340x/340 = 150/340
x = 150/340 = 15/34

4 0

2 years ago