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SashulF [63]
2 years ago
6

One sixth of students at a local college are seniors. The number of freshmen students is 2 1/2 times that amount. What fraction

of the students are freshmen?
Mathematics
2 answers:
vladimir1956 [14]2 years ago
4 0
5/12 because 1/6 equals 2/12. 2 1/2 times 2/12 equals 5/12
Rama09 [41]2 years ago
4 0

Answer: Our required fraction is \dfraac{5}{12}

Step-by-step explanation:

Since we have given that

Fraction of students at a local college = \dfrac{1}{6}

According to question,  The number of freshmen students is 2\dfrac{1}{2}=\dfrac{5}{2} times that amount.

So, Fraction of students are freshmen is given by

\dfrac{5}{2}\times \dfrac{1}{6}\\\\=\dfrac{5}{12}

Hence, our required fraction is \dfraac{5}{12}

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last night, julie's pet hamster zoe kept julie awake for at least an hour running on her exercise wheel and scratching at the co
borishaifa [10]

Answer: x+y\geq 1, x>\frac{1}{4} ,  x\geq 2y and y\geq 0

Step-by-step explanation:

Here,  x represents the number of hours Zoe spent running on her wheel and y represents the number of hours spent scratching her cage.

Julie was awoke for at least an hour running on her exercise wheel and scratching the of her cage.

⇒ x+y\geq 1

She ran on her wheel at least twice as long as she scratched at the corners of her cage.

⇒ x\geq 2y

Also, She spent more than 1/4 hour running on her wheel.

⇒ x>\frac{1}{4}

And, we know that number of hours can not be negative.

⇒  y\geq 0

Therefore, the complete system of inequality which shows the given situation is,

x+y\geq 1, x>\frac{1}{4} and x\geq 2y, y\geq 0

Note: the feasible region ( covered by the given system) is shown in the below graph.


6 0
2 years ago
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
2 years ago
Jay King, owner of a local Bed and Bath Store knows that his customers will only pay at most, $299 for a blow up bed. Assuming J
Roman55 [17]
If you would like to know the price Jay can pay the manufacturer for the blow up bed, you can calculate this using the following steps:

100% + 40% = 140%

140% of x is $299
140% * x = 299
140/100 * x = 299      /*100/140
x = 299 * 100 / 140
x = $213.6

40% of $213.6 = 40% * 213.6 = 40/100 * 213.6 = 85.44
$213.6 + $85.44 = $299

The correct result would be $213.6.
6 0
2 years ago
What are the critical points for g(θ) = 28θ − 7 tan θ
Lelechka [254]
Thank you for posting your question here at brainly. I hope the answer will help you. Below is the solution:

g(θ) = 28θ − 7 tan θ 
g'(θ) = 28 − 7 sec(θ)^2 
0 = 4 - sec(θ)^2 
4 = sec(θ)^2, when θ = ((6*n-1)*pi) / 3 
7 0
2 years ago
The table shows the amount of money LaTasha charges customers to mow their lawns. The table represents a linear function.
sashaice [31]
It is b    Latasha charges 10 dollars before she begins to work

5 0
2 years ago
Read 2 more answers
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