Answer:
Step-by-step explanation:
Let m be number of minutes it will take to download the whole game.
We are told that computer is downloading at a rate of 0.01 GB per minute and half GB game is already downloaded. So 0.01*m+0.5 will be equal to 2.2 as game size is 2.2 GB.
Let us find the least number of minutes it will take to download the whole game.
Therefore, is our desired inequality.
Answer:
25$
Step-by-step explanation:
Add all of the days up and divide by 7
Answer: 43 more times
2580÷60=43.
Step-by-step explanation: 43×60 =2580
This proves that 43 times is correct.
Answer:
Check Below!!
Step-by-step explanation:
This is basically a cool joke.
When we are talking about electricians, we think about
wires, ohms, resistors, insulator, conductor etc.
Since electrician will say something to her daughter who came home LATE AT NIGHT (2am), the joke needs to go hand-in-hand.
Thus, the electrician said:
"Why are you insulate?"
<em>which would mean, why are you in so late?</em>
<em />
<em>HAHA, Good Laugh!</em>
<em>Thanks</em>
Answer:
1. Take the Average of the distances the ball travelled each hit.
2. He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.
3. He should use Mean
4. He should use Median. It best measures skewed data
Step-by-step explanation:
THE FIRST PART.
Raul should take the average of the distances the ball travelled each hit.
This is done by summing the total distances the ball travelled each bounce, and then dividing the resulting value by the total number of times he hit the ball, which is 10.
THE SECOND PART
He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.
THE THIRD PART
He should take the mean of the distances of the ball that stayed infield.
This is the distance that occurred the most during the 9 bounces that stayed infield. The one that went outfield is makes it unfair to use any other measure of the center, taking the mean will give a value that is significantly below his efforts.
THE FOURTH PART
He should take the Median of the data, it is best for skewed data.
This is the middle value for all the distances he recorded.
