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nataly862011 [7]

2 years ago

13

The chemical formula for artificial sweetener is C7H5NO3S. Match the elements with the numbers found in one molecule of artifici

al sweetener.

1 answer:

klio [65]2 years ago

7 0

its is 1.hydrogen 2. oxygen 3. argon 4. carbon

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Write a complete step-by-step plan for dealing with broken glassware on the floor or lab table. Write your plan in list form in

zzz [600]

1 tell the person in charge or the teacher
2 make sure u did not get cut
3 get the large pieces and put them into glass waist container
4 get broom or brush weep area and get small pieces depose in same place
5 take a wet wipe and cover area to pick up anything that as missed!

3 0

2 years ago

Read 2 more answers

Relate text and visuals using the cartoon, explain why the potassium atom becomes positively charged and the fluorine atom becom

tangare [24]

Elements are ionized because they aspire to be stable. The most stable form are the ones with full octet of electrons, the noble gases which consist of the last column in the periodic table. The rest of the elements either accept or readily donate electrons to conform to the electronic configuration that is the same with the nearest noble gas.

1. Potassium's nearest noble gas is Ar which is one electron fewer. So, when ionized, it donates 1 electron. Hence, K⁺.
2. The nearest noble gas for fluorine is Neon which is 1 electron more. Hence, it has to accept one more electron. Hence, F⁻.

5 0

2 years ago

Butane (c4h10) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. given δh°f[c4h10(g)] = –124.7

vagabundo [1.1K]

The value of Δ H butane (g) = -124.7 kJ/mol

The value of Δ H CO2 (g) = -393.5 kJ/mol

The value of Δ H H2O (g) = -241.8 kJ/mol

Mass of butane, m = 8.30 gm

Molar mass of butane is 58 gm/mol

Consider the reaction,

C₄H₁₀ + 6.5 O₂ = 4CO₂ + 5H₂O

Calculating the value of Δ H° rxn:

ΔH°rxn = ∑nH° f (products) - ∑nH° f (reactants)

Substituting the values we get,

Δ H° rxn = 4 (-393.5) + 5 (-241.8) - (-124.7)

= -1574 -1209 + 124.7

= -2783 - 124.7

= -2658.3 kJ/mol

Now, calculate the number of moles of butane in 8.30 gm.

Number of moles = mass/molar mass

= 8.30 / 58

= 0.143 moles

Thus, the total energy released in the reaction is,

Q = number of moles × ΔH° rxn

= 0.143 × (2658.3)

= 380.14 kJ

Hence, the total heat released in the reaction is 380.14 kJ.

6 0

2 years ago

The reaction A + B → 2 C has the rate law rate = k[A][B]³. By what factor does the rate of reaction increase when [A] remains co

lawyer [7]

Answer:

8

Explanation:

To solve this question, we just need to put the new number into the equation. If [A] remain constant then that mean [A2]= [A1]. If B doubled, then that mean [B2]= 2[B2]. To find what factor does the rate of reaction increases, we need to divide the first reaction rate with the second. The calculation will be:

rate2/rate1= k[A2][B2]³ / k[A1][B1]³

rate2/rate1= [A1][2B1]³ / [A1][B1]³

rate2/rate1= A1*8B1³ / A1*B1³

rate2/rate1= 8/1= 8

The rate of reaction will be 8 times faster.

7 0

2 years ago

A thin sheet of iridium metal that is 3.12 cm by 5.21 cm has a mass of 87.2 g and a thickness of 2.360 mm. What is the density o

never [62]

Answer:

Therefore the density of the sheet of iridium is 22.73 g/cm³.

Explanation:

Given, the dimension of the sheet is 3.12 cm by 5.21 cm.

Mass: The mass of an object can't change with respect to position.

The S.I unit of mass is Kg.

Weight of an object is product of mass of the object and the gravity of that place.

Density: The density of an object is the ratio of mass of the object and volume of the object.

$Density =\frac{mass}{volume}$

$=\frac{Kg}{m^3}$ [S.I unit of mass= Kg and S.I unit of m³]

Therefore the S.I unit of density = Kg/m³

Therefore the C.G.S unit of density=g/cm³

The area of the sheet is = length × breadth

=(3.12×5.21) cm²

=16.2552 cm²

Again given that the thickness of the sheet is 2.360 mm =0.2360 cm

Therefore the volume of the sheet is =(16.2552 cm²×0.2360 cm)

=3.8362272 cm³

Given that the mass of the sheet of iridium is 87.2 g.

$Density =\frac{87.2 g}{3.8362272 cm^3}$

=22.73 g/cm³

Therefore the density of the sheet of iridium is 22.73 g/cm³.

5 0

2 years ago