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2 years ago

. Which is equivalent to a drink made with 3 ounces of 80-proof vodka?

Mathematics

2 answers:

nasty-shy [4]2 years ago

8 0

Omg frat part y lsolldlddld

maksim [4K]2 years ago

5 0

Answer:

A Dry martini

Step-by-step explanation:

The martini drink which is known as a non-light drink, it is often at times served on a short way, and rarely poured over 5 ounces to a customer or an individual.

The Martini as described weighs around 30 to 31 percent ABV, which is 62 of proof. it comes with a standard 80-proof gin and has 15 percent alcohol Light) by volume ( ABV ).

A dry martini drink is more described or compared with a vodka having a 3 ounces of 80-proof gin, and a shot of 100-proof whiskey of 5 ounces, 3 ounces of cranberry juice , 7 ounces of a carbonated beverage and 1.5 ounces of 80-proof vodka.

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Two linear functions are shown below which function has the greater rate of change

Shtirlitz [24]

Answer:

On this case if we analyze both slopes, we see that function 2 has a greater rate of change because have a slope greater on absolute value than the slope for Function 1 (|-5|>|4|). No matter if the sign is positive or no we are analyzing the rate of change and for this case we need to use the absolute value to find the solution.

Step-by-step explanation:

Assuming the following two functions:

Function 1: y = 4x + 8

Function 2:

x y

2 20

4 10

6 0

We can find the slope for the second function like this:

$m =\frac{10-20}{4-2}=-5$

And in order to find the intercept we can use any point for example (2,20) and we got:

$20 =-5(2) +b$

And then $b=30$

So our function 2 is given by: $y =-5x +30$

7 0

2 years ago

Ms. berkin is dividing her 4 1/2-foot by 6-foot bulletin board into 4 sections with ribbon stretched from each corner to the opp

Mnenie [13.5K]

Answer:

15 feet.

Step-by-step explanation:

A bulletin board has been shown in the figure below.

Where the width of the board AB = DC = $4\frac{1}{2}$ = 4.5 feet

and the length of the board AD = BC = 6 feet

As Ms. Berkin is dividing the board by stretching the ribbons to the opposite corners so the length of ribbons will be AC and BD.

In right angle triangle ADC, using Pythagorean Theorem,

$AC^2=AD^2+DC^2$ = $6^2+4.5^2=36+20.25=56.25$

$AC= \sqrt{56.25} = 7.5$ feet

Similarly in triangle BDC,

$BD^2=BC^2+DC^2 = 6^2+4.5^2=36+20.25 =56.25$

$BD=\sqrt{56.25} = 7.5$ feet

Thus, total length of the ribbon used = AC + BD = 7.5 + 7.5 = 15 feet

3 0

3 years ago

Mia has a conical container filled with chocolates. She knows that the volume of the container is equal to one-third of the prod

34kurt

For this case what you should do is create the equation based on:
"She knows that the volume of the container is equal to one-third of the product, the square of the radius of the base of the container, and the height of the container"
We have then that the Volume is given by:
V = (1/3) * (r ^ 2) * (h)
where,
r: radius of the base.
h: height of the container.
answer
The volume of the container is calculated with the following equation:
V = (1/3) * (r ^ 2) * (h)

7 0

2 years ago

Read 2 more answers

For flights from a particular airport in January, there is a 30 percent chance of a flight being delayed because of icy weather.

lyudmila [28]

Answer:

0.335

Step-by-step explanation:

1. There is a 30 percent chance of a flight being delayed because of icy weather ,then the probability of being delayed is 0.3 and of being not delayed is 0.7.

2. If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem, then the probability of being delayed is 0.1 and the probabilty of not being delayed is 0.9.

3. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem (MP), then the probability of being delayed is 0.05 and the probabilty of not being delayed is 0.95. (See attached probability tree)

Delayed of icy weather - 0.3

Delayed of MP when weather is not icy - 0.7·0.05=0.035

Now, if one flight is selected at random from the airport in January, the probability that the flight selected will have at least one of the two types of delays is

0.3+0.035=0.335

8 0

2 years ago

Sitting at the edge of a cliff, you throw a stone vertically upward with a velocity of 30 m/s. The height of the stone above the

Oksanka [162]

Answer:

Step-by-step explanation:

Given that,

The function f(t) = 3t − 0.5t² is the height of the motion of the stone in 10m units

And it's initial velocity is 30m/s

u=30m/s

Using calculation

Let find it turning point

f(t) = 3t − 0.5t²

Then, f'(t) =3-t

f(t)=0

So, 0=3-t

Then t=3secs

So let know the inflection point to show if t=3secs is the maximum point or minimum point

Then, we need second integral of f(t)

f'(t) = 3 − t

f''(t)=-1

Since f''(t) is negative this shows that the point is the maximum point

So at t=3secs is the maximum point,

So now to know the maximum point

f(t) = 3t − 0.5t²

t=3secs

f(t)=3(3)-0.5(3)²

f(t)=9-4.5

f(t)=4.5m

Since f(t) is in 10m units

Then,

The height is f(t) =10×4.5

f(t) =45m

Then the maximum height of the stone is 45m and the time to reach the maximum height is t=3secs

Now, Using equation of motion

Time to reach max height.

v=u-gt. Upward motion g=9.81m/s2

Final velocity is v=0m/s

0=30-9.81t

-30=-9.81t

t=-30/-9.81

t=3.06secs

t=3.1secs. To 1d.p

If we have used g=10m/s², it will have the same value as the graph and the maximum and minimum point calculation

Maximum height, using equation of motion

v²=u²-2gH

0²=30²-2×9.81H

-30²=-19.62H

Then,

H=-30²/-19.62

H=45.87

a. From the graph it shows that the maximum value of the is 4.5m at time t=3secs

b. Now, the maximum height of stone as shown on the graph is 4.5m

And since is 10 meter unit scale

Then the height becomes 4.5×10

Maximum height is 45m.

c. The stone will spend two times the time it uses to reach t maximum height to return to the height of the cliff

Time to return back to the cliff is

T=2t

T=2×3

T=6secs

d. If the stone hits the ground after t=7secs

So after the ball reached a maximum height of 45m, he has spent 3secs, so we can calculate the distance the stone travelled from the maximum to the ground

The time is of travel will be 4secs

Then,

Initial velocity is 0, from the point of return at rhe maximum height

S=ut+½gt²

S=0+½×9.81×4²

S=78.48m

So the total distance from the maximum height down to the bottom of the cliff is 78.48m

Then, the height of the cliff is the height from the maximum height to the bottom of the cliff minus the maximum height reach by the stone

Then,

H(cliff)=78.48-45.87

H(cliff)=33.48m

From the graph

At t=7secs

The stone is at a distance of -3.5m

Showing that the height of the cliff

Since it is of 10m units

Then the height of the cliff is

3.5×10=35m

Also

f(t) = 3t − 0.5t² at t=7secs

F(7)=3(7)-0.5(7)²

F(7)=21-0.5×49

F(7)=21-24.5

Then,

f(7)=-3.5m

This shows the downward motion

Since it is 10m unit

The the height of cliff downward is

3.5×10=35m

Height of cliff =35m

3 0

2 years ago