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bixtya [17]
2 years ago
12

Density is equal to mass divided by volume. The mass of a metal is 10.34 g. Its volume is 1.83 ml. Calculate its density. Use th

e proper number of significant figures.
Mathematics
2 answers:
marishachu [46]2 years ago
7 0

Answer: 5.65 g/ml

Step-by-step explanation:

The density of a substance is given by :-

\text{Density}=\dfrac{\text{Mass}}{\text{Volume}}

Given : The mass of a metal is 10.34 g. Its volume is 1.83 ml.

Then, the density of substance will be :-

\text{Density}=\dfrac{10.34\ g}{1.83\ ml}\\\\\Rightarrow\ \text{Density}= 5.65027322404\ g/ml

Since , the significant figures depend on the dividend .

Here the dividend (10.34) is hundredth unit.

Then, the \text{Density}== 5.65027322404\approx5.65\ g/ml

Tamiku [17]2 years ago
5 0
Density = 10.34/1.83

Density = 5.65027

Significant figures is based on the lowest digit that was divided, which is to the hundredth unit.

In conclusion, the density is 5.65 g/ml^3
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A cooling tower for a nuclear reactor is to be constructed in the shape of a hyperboloid of one sheet. The diameter at the base
timurjin [86]

Answer:

Step-by-step explanation:

Equation for a hyperboloid of one sheet, with center at the origen and axis along z-axis is:

(x/a)²  +  (y/b)²   -  (z/c)²  =  1                         (1)

We have to find a , b, and c

We can express equation (1)

(x/a)²  +  (y/b)²    =  (z/c)² + 1                 (2)

Now if we cut the hyperboloid with planes parallel to xy plane we get for  z = k       ( K = 1 , 2 , 3  and so on ) circles of different radius

(x/a)²  +  (y/b)²    =  (k/c)² + 1

at z = k = 0 at the base of the hyperboloid  d = 300   or r = 150 m

we have

(x/a)²  +  (y/b)²   = 1      

x²  +  y²   =   a²                a² = (150)²       a = b = 150

and    x²  +  y²  = (150)²

Now the other condition is at 200 m above the base d = 500 m   r = 250 m  minimum diameter then in equation (2)  we have:

(x/a)²  +  (y/b)²    =  (z/c)² + 1        

(1/a)² [ x² + y² ]  = (z/c)² + 1  

but   x²  +  y²  = r²    and in this case   r  =  250 m  then

(250)²/(150)²   =  (z/c)² + 1    ⇒ (62500/ 22500)  =  (200/c)² + 1

2,78  =  40000/c² + 1

2.78c²  =  40000  + c²

1.78c² = 40000

c²  =  40000/1.78

c²  = 22471.91

c = 149,91

Then we finally have the equation:

x²/(150)²   + y² /(150)² - z²/149,91  = 1

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